Measure 1 would be 59 degrees (180-121)
Measure 2 would be 121 degrees (vertical angle theorem)
Answer:
Angle A is 29 degress Angle B is 61 Angle C is 90
Side AB is 5.8 Side BC is 2.8 and Side AC is 5.1
Step-by-step explanation:
Angle A is found using triangle interior theorem.
I found side AC by using law of sines
b/sin b= c/sin c
x/sin 61= 5.8/sin 90( which equal 1)
x=5.1
I found side BC by using pythagoren theorem.
a^2 + b^2=c^2
5.1^2+ b^2=5.8^2
26.01+b^2=36.64
b^2=7.63
b=approx 2.8.
For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
Answer:
58
Step-by-step explanation:
The triangles are congruent so you can do 180-32-90, which is equal to the angle at c
Answer:
The answer is A. 133
Step-by-step explanation:
84 + 92 + 87 + 104 = 367
367 + 133 = 500