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jenyasd209 [6]
4 years ago
13

Help me with this please

Mathematics
2 answers:
Inessa [10]4 years ago
6 0
We can't see what you need help with by this picture sorry.
natita [175]4 years ago
5 0
Could you maybe rotate the picture so we can see it better?
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Find the number if: 4% of it is 31% of 16.4
alisha [4.7K]

Answer:

The number (x) is 127.1

Step-by-step explanation:

4% of a number (x) is equal to;

31% of 16.4

i.e 0.04x = 5.084

x = \frac{5.084}{0.04} = 127.1

The number (x) is 127.1

3 0
4 years ago
Read 2 more answers
Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards. If the actual width of a neighborhood park is 62 yard
klemol [59]

Answer:

The park is <u>31 inches</u> wide in the drawing.

Step-by-step explanation:

Given:

Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards.

The actual width of a neighborhood park is 62 yards.

Now, to find the width of park in drawing.

Let the width of park in drawing be x.

The scale drawing of the city is 1 inch : 2 yards.

So, 1 inch is equivalent to 2 yards.

Thus, x is equivalent to 62 yards.

Now, to get the width of park in drawing by using cross multiplication method:

\frac{1}{2} =\frac{x}{62}

By cross multiplying we get:

62=2x

Dividing both sides by 2 we get:

31=x

x=31\ inches.

Therefore, the park is 31 inches wide in the drawing.

8 0
3 years ago
Harry is 45 years old is 60% as old as Patrick .How old is Patrick
Ainat [17]

Answer:

it is 27.

Step-by-step explanation:

60 percent of 45 is 27.

3 0
3 years ago
How is the graph of y = -8x2 - 2 different from the graph of y = -8x2?
Aleks04 [339]

Answer:

(Answer D)

Step-by-step explanation:

Please use " ^ " to indicate exponentiation:  y = -8x^2 - 2, y = -8x^2

The graph of y = -8x^2 is an inverted parabola with vertex at (0, 0).

That of y = -8x^2 - 2 is the same as above, except that the whole graph has been shifted 2 units down (Answer D).

4 0
3 years ago
Solve 4 cos2x-3 = 0 for all real values of x.
vichka [17]

4 cos² x - 3 = 0

4 cos² x = 3

cos² x = 3/4

cos x = ±(√3)/2

Fixing the squared cosine doesn't discriminate among quadrants.  There's one in every quadrant

cos x = ± cos(π/6)

Let's do plus first.  In general, cos x = cos a has solutions x = ±a + 2πk integer k

cos x = cos(π/6)

x = ±π/6 + 2πk

Minus next.

cos x = -cos(π/6)

cos x = cos(π - π/6)

cos x = cos(5π/6)

x = ±5π/6 + 2πk

We'll write all our solutions as

x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k

3 0
3 years ago
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