I am only in my first year of 12th grade.
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Answer:
Perimeter of the paperboard that remains after the semicircle is removed = 94.26 in
Step-by-step explanation:
Watch the attached figure of how the semi circle is cut out of the rectangular paperboard.
Length = 24 in
Width = 18 in
Radius of the semi circle = Half of the width of the paperboard = = 9 in
1) Circumference of the semi circle = π*radius
= 3.14*9
= 28.26 in
2) Perimeter of the paperboard that remains after the semicircle is removed
= Top + Left + Bottom + Right Circumference of the semi circle
= 24 + 18 + 24 + 28.26
= 94.26 in
Domain: x² - 4 ≠ 0
+ 4 + 4
x² ≠ 4
√x² ≠ √4
x ≠ ±2
x ≠ -2 and x ≠ 2
(-∞, -2) ∨ (-2, 2) ∨ (2, ∞)
Range: y ≠ 1
(-∞, 1) ∨ (1, ∞)
Intervals: Increasing: (0.25 , ∞)
Decreasing: (-∞, 0.25)
Symmetry: X-axis: Not Symmetric
Y-axis: Not Symmetric
Origin: Not Symmteric
Extrema: Maximum Relative: x = 0
Minimum Relative: Nothing