Answer:
(a) Test statistic is -2.85 and p-value is 0.0022
(b) Reject the null hypothesis. The population mean of dissolved oxygen content is not equal to 10 mg/L
Step-by-step explanation:
H0: mu equals 10
Ha: mu not equals 10
The test is a two-tailed test because the alternate hypothesis is expressed using not equal to
(a) Test statistic (z) = (sample mean - population mean) ÷ (sd/√n) = (9.14 - 10) ÷ (2/√44) = -0.86 ÷ 0.302 = -2.85
Cumulative area of the test statistic = 0.9978
p-value = 2(1 - 0.9978) = 2(0.0022) = 0.0044
(b) The critical value using 0.02 significance level is 2.422. For a two-tailed test, the region of no rejection of the test statistic lies between -2.422 and 2.422.
Conclusion:
Reject the null hypothesis because the test statistic -2.85 falls outside the region bounded by the critical values -2.422 and 2.422.
The population mean of dissolved oxygen content is not equal to 10 mg/L
Answer:
All of them
Step-by-step explanation:
Answer:
Frieda's work is correct.
Step-by-step explanation:
z+22= 64 can also be z= 64-22
64-22= 42
Meaning, z= 42
42+22-22= 64-22
42= 42
Answer:
For not exact divisions: Writing the results as Quotient + Remainder over the Divisor.
For exact division: just the quotient.
Step-by-step explanation:
Hi there,
In both algorithms, for long and synthetic divisions we must write the result as an expression following that order:
When the Division leaves no Remainder, i.e. an exact, the Remainder is equal to zero, so
Check below for the algorithms for each division and the way of writing their expressions (results).
