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son4ous [18]
4 years ago
5

A theater group made appearances in two cities. The hotel charge before tax in the second city was $1000 lower than in the first

. The tax in the first city was 7.5% , and the tax in the second city was 5% . The total hotel tax paid for the two cities was $575 . How much was the hotel charge in each city before tax?
Mathematics
1 answer:
Bess [88]4 years ago
8 0

Answer:

  • $5000 in the first city
  • $4000 in the second city

Step-by-step explanation:

Let x represent the pre-tax hotel charge in the first city in dollars. Then the hotel charge in the second city is x-1000 dollars, and the total tax is ...

... 7.5%·x +5%·(x -1000) = 575

... 12.5%·x = 625 . . . . simplify, add 50

... x = 5000 . . . . . . . . divide by 12.5% (=0.125)

The first-city charge was $5000; the second-city charge was $4000.

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Answer:

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Step-by-step explanation:

Lets go first with 3x – 8 < 23  then with - 4x + 26 > 6 and after that we put them together. (I will use the < > signs but as I see on the pictures these include the =, being less and greater OR equal).

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Lets sum 8 in both sides:

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It is the option B in the image (remember I didnt use the less or equal sign because you didn't included it in the statement).

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