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3 years ago

6

Find the ordered pairs for the x- y-intercepts of the equation 4x+2y=16

1 answer:

erastovalidia [21]3 years ago

3 0

The x-intercept is what 'x' is when 'y' is equal to 0. So plug in 0 for 'y' and solve for 'x':

$\sf 4x+2y=16$

$\sf 4x+2(0)=16$

Simplify:

$\sf 4x=16$

Divide 4 to both sides:

$\sf x=4$

So the x-intercept is (4, 0).

The y-intercept is what 'y' is when 'x' is equal to 0. So plug in 0 for 'x' and solve for 'y':

$\sf 4x+2y=16$

$\sf 4(0)+2y=16$

Simplify:

$\sf 2y=16$

Divide 2 to both sides:

$\sf y=8$

So the y-intercept is (0, 8).

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3 years ago

The cost of painting the total outside surface of a closed cylindrical tank at 60 paise per meter squae is Rs237.60. The height

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Step-by-step explanation:

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2 years ago

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irakobra [83]

Answer:

The correct option is 1/4^2

Step-by-step explanation:

The given expression is:

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According to the same base rule if the exponents have the same base then the exponents will be added.

If we look at the given expression both the values have the same base.

Therefore we will add the exponents of the value.

= 4^6+(-8)

= 4^6-8

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Thus the correct option is A....

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