Question

Find the ordered pairs for the x- y-intercepts of the equation 4x+2y=16

Answer 1

The x-intercept is what 'x' is when 'y' is equal to 0. So plug in 0 for 'y' and solve for 'x':

$\sf 4x+2y=16$

$\sf 4x+2(0)=16$

Simplify:

$\sf 4x=16$

Divide 4 to both sides:

$\sf x=4$

So the x-intercept is (4, 0).

The y-intercept is what 'y' is when 'x' is equal to 0. So plug in 0 for 'x' and solve for 'y':

$\sf 4x+2y=16$

$\sf 4(0)+2y=16$

Simplify:

$\sf 2y=16$

Divide 2 to both sides:

$\sf y=8$

So the y-intercept is (0, 8).