Answer:
1/sqrt10
Step-by-step explanation:
1) Find out cosA using formula (cosA)^2+(sinA)^2=1
The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5
So cosA=-4/5 or cosA=4/5.
Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.
2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.
(sinA/2)^2= 0.1
sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10
But 270°< A< 360°, then 270/2°<A/2<360/2°
135°<A/2<180°, so sinA/2 must be positive and the only correct answer is
sin A/2= 1/sqrt10
12 divuded by3=4, 12 dibed by 4=3, 12 divided by 6=2, 12dibided by 2=6, 12 divided by1=12, 12 divided by 12=1
Answer:
D)
Step-by-step explanation:
this is the answer
I hope this helps. If not, feel free to leave a feedback. also leave a comment if it helped.
Answer: 16
Step-by-step explanation: 27-11=16
