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3 years ago

The line 5y−6x−10=0 is given.What is the slope of this line?

Mathematics

2 answers:

pogonyaev3 years ago

5 0

The slope of the line is 6/5

Feliz [49]3 years ago

3 0

Answer:I think it is 6/5

Step-by-step explanation:hope I helped

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The list shows the number of songs on each album Dakota has downloaded.

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The histogram looks similar to the stem and leaf plot, except turned on its side. It is different from the frequency table in shape, but the numbers in the table are the same as the size of the bars.

The height of the bars in the histogram is the same as the number of leaves in the stem and leaf plot, and it is also the same as the numbers in the frequency table. Using larger intervals will result in larger bars on the histogram and larger numbers in the frequency table; smaller intervals will result in smaller bars and smaller numbers in the table.

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Draw three circles with centre 0 and the radii of 3cm, 5cm and 7cm respectively

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2 years ago

ΔABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C?

kotykmax [81]

Answer:

$cos(C) =\frac{40}{41}\\\\cos(C)=0.976$

Step-by-step explanation:

To find the $cos (C)$ we must use the cosine theorem.

The cosine theorem says that:

$c^2 = a^2 +b^2 -2abcos(C)$

In this case:

$c=AB = 9$

$b=CA = 41$

$a=BC = 40$

$9^2 = 40^2 +41^2 -2(40)*(41)cos(C)$

$9^2- 40^2- 41^2 =-2(40)*(41)cos(C)$

$cos(C) = -\frac{9^2- 40^2- 41^2}{2(40)*(41)}$

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7 0

3 years ago

for any positive integer n, the sum of the first n positive integers equals n(n 1)/2. what is the sum of all the even integers b

marusya05 [52]

The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

⇒ 300 = 100 + (n-1) x 2

Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

= 101/2 (300+100)

= 20200

Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

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7 0

1 year ago