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RideAnS [48]
3 years ago
9

In glycolysis, for each molecule of glucose oxidized to pyruvate A. 2 molecules of ATP are used and 2 molecule of ATP are produc

ed. B. 2 molecules of ATP are used and 4 molecules of ATP are produced. C. 4 molecules of ATP are used and 2 molecules of ATP are produced. D. 2 molecules of ATP are used and 6 molecules of ATP are produced. E. 6 molecules of ATP are used and 6 molecules of ATP are produced.
Biology
1 answer:
Roman55 [17]3 years ago
7 0
<h3><u>Answer</u>;</h3>

B. 2 molecules of ATP are used and 4 molecules of ATP are produced.

<h3><u>Explanation</u>;</h3>
  • Glycolysis is the first phase of ecllular respiration that converts one six-carbon molecule of glucose into two three-carbon molecules of pyruvate.
  • One glucose molecule produces four ATP, two NADH, and two pyruvate molecules during glycolysis.
  • The net products of this process are two molecules of ATP, since four molecules of ATP are produced and 2 ATP molecul;es are used, and two molecules of NADH.
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The bacterium E. coli is capable of performing aerobic respiration, anaerobic respiration, and fermentation. When would it perfo
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Answer:

1. Aerobic respiration: when oxygen is present.

ATP is made by <u>respiratory linked phosphorylation</u>.

2. Anaerobic respiration: when oxygen is absent. For example, in the gut of mammals.

ATP is made by <u>substrate-level phosphorylation</u>.

3. Fermentation: this is the last resort or least preferred process after aerobic and anaerobic respiration, respectively. This is achieved in conditions of oxygen absence (anaerobic conditions) and when energy (ATP) is not required in high levels.

ATP is made by <u>substrate-level phosphorylation</u>.

Explanation:

<em>Escherichia coli </em>is a Gram-negative species of versatile bacterium that is not only able to grow when oxygen is present (aerobic conditions), but it can also adapt to different conditions and grow in the absence of oxygen using either anaerobic respiration or fermentation. This is a great adaptation because it allows it to grow in a wide variety of environments.

1. Aerobic respiration: <em>when oxygen is present. It is the most preferred mechanism to produce ATP as conditions are optimal. </em>

ATP is made by <u>respiratory linked phosphorylation</u>.

<em>*Metabolism releases energy and is captured by the phosphate bonds of ATP.</em>

2. Anaerobic respiration: <em>when oxygen is absent. For example, in the gut of mammals. The second preferred mechanism to produce energy because it does not produce as much energy as aerobic respiration does.</em>

ATP is generated by <u>substrate phosphorylation</u>.

<em>*Phosphate groups are directly transferred during the conversion of ADP into ATP.</em>

3. Fermentation: <em>this is the last resort or least preferred process after aerobic and anaerobic respiration, respectively, because it produces even less ATP. This is achieved in conditions of oxygen absence (anaerobic conditions) and when energy (ATP) is not required in high levels. </em>

ATP is made by <u>substrate-level phosphorylation</u>.

<em>*Phosphate groups are directly transferred during the conversion of ADP into ATP.</em>

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4 years ago
In a population of gerbils ,long hair is completely dominant over short hair .if 18percent of the population has short hair , ca
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Answer: 49%

Explanation:

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*first use the equation to solve for the known value 18% hh

.18 = q^2

Square root .18 = q

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Which will give you the frequency of dominant alleles

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Then just plug the P and q values found into the portion of the equation for heterozygous offspring.

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Which is .49 or 49%

The entire population should be 33% homozygous dominant 49% heterozygous and 18% homozygous recessive.

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