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mezya [45]
3 years ago
10

Write an equation in slope-intercept form that passes through the point (1,3) and has a slope of -3.

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
6 0
Y=-3x+6
simplest way to find this is to graph the point (1,3) and then go up three and back one (since the slope is -3 and its rise over run) to fine that it hits the y axis at 6 so the line is y=-3x+6  
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Find the value of 7w-8 given that -4w-5=3<br> Simplify your answer as much as possible.<br> 7w - 8 =
blondinia [14]

Answer:

The value of 7w - 8 is -22

Step-by-step explanation:

Let us solve the question

∵ -4w - 5 = 3

→ Move -5 from the left side to the right side by adding both sides by 5

∴ -4w - 5 + 5 = 3 + 5

∴ -4w = 8

→ Divide both sides by -4

∵ \frac{-4w}{-4} = \frac{8}{-4}

∴ w = -2

→ Now let us find the value of the given expression

∵ The given expression is 7w - 8

→ Substitute w by -2 to gets its value

∴ 7w - 8 = 7(-2) - 8

∴ 7w - 8 = -14 - 8

∴ 7w - 8 = -22

∴ The value of 7w - 8 is -22

8 0
3 years ago
What is y
kogti [31]

Step-by-step explanation:

Looks like you want all equations converted into slope-intercept form.

  • 2x + y = 2 ⇒ y = -2x + 2
  • x + 2y = 4 ⇒ 2y = - x + 4 ⇒ y = - 1/2x + 2
  • 2x - y = 2  ⇒ y = 2x - 2
  • x - 2y = 4  ⇒ 2y = x - 4 ⇒ y = 1/2x - 2
3 0
2 years ago
Read 2 more answers
Please help its for a grade.
Kamila [148]

Answer:

See below

Step-by-step explanation:

<u>Taking the readings from the graph</u>

  • <u>x ....  y</u>
  • 0 .... 2
  • 2 .... 6
  • 4 .... 10
  • 6 .... 14

<u>Rate of change for the given line is:</u>

  • (6 - 2)/2 = 4/2 = 2
  • y- intercept is 2

<u>Equation for the line is:</u>

  • y = 2x + 2

<u>For the point (40, 76) we can verify with the equation:</u>

  • 40*2 + 2 = 82

The point (40, 76) is close the line but the line doesn't pass through it.

6 0
3 years ago
Read 2 more answers
Rewrite each expression as a polynomial in standard form: x^2-5x+6 ÷ x-3 + x^3-1 ÷ x-1
iragen [17]

Answer:

So in standard form equation will be x^2+2x-1

Step-by-step explanation:

We have given expression \frac{x^2-5x+6}{x-3}+\frac{x^3-1}{x-1}

Let first we solve first part of the expression

So \frac{x^2-5x+6}{x-3}=\frac{x^2-3x-2x+6}{x-3}=\frac{(x-3)(x-2)}{x-3}=x-2

Now second part \frac{x^3-1}{x-1}

We know the algebraic identity a^3-b^3=(a-b)(a^2+ab+b^2)

So by using this identity

\frac{x^3-1}{x-1}=\frac{(x-1)(x^2+x+1)}{x-1}=x^2+x+1

Now adding first and second part

x-2+x^2+x+1=x^2+2x-1

So in standard form equation will be x^2+2x-1

4 0
3 years ago
Is this correct? Please help me due today.
gulaghasi [49]
The answer you just put is correct
5 0
3 years ago
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