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svetlana [45]
3 years ago
5

Which of the following shows that polynomials are closed under addition when two polynomials 4x2 − 8x − 7 and −5x + 16 are added

?
4x2 − 13x + 9 may or may not be a polynomial

4x2 + 13x − 23 may or may not be a polynomial

4x2 − 13x + 9 will be a polynomial

4x2 + 13x − 23 will be a polynomial
Mathematics
2 answers:
Alisiya [41]3 years ago
8 0

Answer:

the answer is C.

4x2-13x+9 will be a polynomial

Step-by-step explanation:

it was right on my test hope this helps byeeeeeeeeee

zavuch27 [327]3 years ago
5 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Among the choices the one that  shows that polynomials are closed under addition when two polynomials 4x2 − 8x − 7 and −5x + 16 are added is <span>4x2 − 13x + 9 will be a polynomial</span>
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A shoreline observation post is located on a cliff such that the observer is 280 feet above sea level. The observer spots a ship
morpeh [17]

Answer:

Step-by-step explanation:

a) D/280 = tan(90 - 6)

   D = 280tan84 = 2,664 ft

b) D/280 = tan(90 - 16)

   D = 280tan74 = 976 ft

ship speed = (2664 - 976) / 43 = 39.2 ft/s

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Please answer these questions asap please!!! Thank you!
Len [333]

Answer:

a= 1%

b= 0.1%

c= 0.1875% probably have to round

Step-by-step explanation:

a= 2/2= 1

B= 1/10=0.1

c= 1.5/8= 0.1875

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What is the greatest common factor of 24s3, 12s4, and 18s?
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The following observations are on stopping distance (ft) of a particular truck at 20 mph under specified experi- mental conditio
zzz [600]

Answer:

see explaination

Step-by-step explanation:

Data : 32.1 , 30.6 , 31.4 , 30.4 , 31.0 , 31.9

Mean X-bar = 31.23

SD = 0.689

a)

Null Hypothesis : Xbar = mu

Alternate Hypothesis : Xbar > mu

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 30 ) /(0.689/sqrt(6))

= 4.372

P-value = ~0

Since P-vale < 0.01 , we will reject null hypothesis.

The data suggest that true average stopping ditance exceeds the maximum.

b)

i) SD = 0.65

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.65/sqrt(6))

= 0.867

P-value = 0.3859 Answer

ii) SD = 0.65

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.65/sqrt(6))

= -2.9

P-value = 0.0037 Answer

c)

i) SD = 0.8

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.8/sqrt(6))

= 0.704

P-value = 0.4814 Answer

ii) SD = 0.8

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.8/sqrt(6))

= -2.357

P-value = 0.0184 Answer

The probabilities obtained in part c are comparatively higher than that of part b.

d)

i) For alpha =0.01

z = (Xbar - mu) / (SD/sqrt(n))

=> -2.32 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-2.32

=> sqrt(n) = (0.65*(-2.32)) / (31.23 - 31)

=> n = 43 Answer

ii) For beta =0.10

z = (Xbar - mu) / (SD/sqrt(n))

=> -1.28 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-1.28

=> sqrt(n) = (0.65*(-1.28)) / (31.23 - 31)

=> n = 13 Answer

4 0
2 years ago
What is 350X40= SHOW WORK PLZ HELP ME
Tomtit [17]
2
350
x 40
____
000
1400
____
1,400

8 0
3 years ago
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