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3 years ago

14

cirrus clouds form more than 6,000 meters above earth. write Aand inequality to represent h, the height, in meters, of cirrus cl

ouds

1 answer:

labwork [276]3 years ago

4 0

I hope that helps:
h>6000

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Solve 7 3/4- 5 5/4=

Kaylis [27]

Hey!

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Solution:

(5/4 = 1 1/4) and (1 1/4 + 6 = 6 1/4)

= 7 3/4 - 6 1/4 (5/4 = 1 1/4)

= 1 2/4 or 1 1/2

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Answer:

1 2/4 or 1 1/2

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Hope This Helped! Good Luck!

8 0

3 years ago

What does 18 lb=___________oz

SVETLANKA909090 [29]

So,

First, the conversion between pounds and ounces is:
1 lb. = 16 oz.

So:
18 lbs. = 16 * 18 = 288 oz.

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3 years ago

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On the coordinate grid of a map, Josie's house is located at (2,7). Her school is located at (-5,5). If each map unit equals one

oksian1 [2.3K]

To find the distance you would use the distance formula which is:
$d = \sqrt{(x2-x1)^{2}+(y2-y1)^{2}} = \sqrt{(2-(-5))^{2}+(7-5)^{2}}$

This equals:
$d = \sqrt{(7)^{2}+(2)^2} = \sqrt{49+4} = \sqrt{53} = 7.2801$

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3 years ago

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X=? Y=6<br> 75 degree angle at (0,0)<br> What is X?

choli [55]

Answer:

$X=12-6\sqrt{3}=1.6077$

Step-by-step explanation:

Given that $Y=6$

$\tan(75)=\frac{Y}{X} \\X=\frac{Y}{\tan(75)}=Y\cot75=6\cot75 \\\\Calculate \ \cot(75)\\\tan(75)=\tan(45+30)=\frac{\tan45+\tan30}{1-\tan45 \cdot \tan30} =\frac{1+\frac{1}{\sqrt{3} } }{1-\frac{1}{\sqrt{3} } } \\\tan75=\frac{\sqrt{3}+1 }{\sqrt{3}-1 } =2+\sqrt{3} \\\cot75=\frac{1}{2+\sqrt{3} } =\frac{2-\sqrt{3} }{2^2-3} =2-\sqrt{3} \\\\Hence\\X=6\cot75=6 \cdot(2-\sqrt{3})\\X=12-6\sqrt{3} \approx1.6077$

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3 years ago

What is the difference between the mean and the median of the data set?<br> {22, 8, 10,18,12, 20)

Marrrta [24]

Answer: They are both the same

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3 years ago