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dangina [55]
4 years ago
5

Given right triangle XYZ what is the value of tan 60°

Mathematics
2 answers:
algol [13]4 years ago
8 0
I have attached the image associated with this question

Answer:
tan (60) = √3

Explanation:
The given triangle is right-angled triangle, therefore, we will use Pythagorean theorem to get the length of the third side.
third side = sqrt [(hypotenuse)^2 + (second side)^2]
third side = 21√3 units

Since the given triangle is a right-angled triangle, we can apply the special trigonometric identities.
Therefore:
tan θ = opposite / adjacent
In the given triangle:
θ = 60°
The opposite side = 21√3
The adjacent side = 21

Substitute in the above equation to get tan 60 as follows:
tan (60) = (21√3) / (21) = √3

Hope this helps :)

alex41 [277]4 years ago
6 0

Answer:

√3

Step-by-step explanation:

got 100%

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A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6
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Answer:

Part a) The height of the ball after 3 seconds is 49\ ft

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

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[0,4]

Step-by-step explanation:

we have

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Part a) What is the height of the ball after 3 seconds?

For t=3 sec

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Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

so

Convert the function into a vertex form

h(t)=-16t^{2} +63t+4

Group terms that contain the same variable, and move the constant to the opposite side of the equation

h(t)-4=-16t^{2} +63t

Factor the leading coefficient

h(t)-4=-16(t^{2} -(63/16)t)

Complete the square. Remember to balance the equation by adding the same constants to each side

h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})

h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})

Rewrite as perfect squares

h(t)-(67,600/1,024)=-16(t-(63/32))^{2}

h(t)=-16(t-(63/32))^{2}+(67,600/1,024)

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we know that

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so

h(t)=-16t^{2} +63t+4

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0=-16t^{2} +63t+4

using a graphing tool

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see the attached figure

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