the length of a rectangle is more 3 more than the width. find the length of the rectangle if the perimeter is 98in

2 answers:

Citrus2011 [14]3 years ago

8 0

Let width be w
and length be l
therefore l = 3 + w

perimeter = 2( l + w )
98 = 2(3 + w + w)
98 = 6 + 2w + 2w
98 - 6 = 4w
92 = 4w
92/4 = w
23 = width
width = 23 inches

As l = 3 + w ,
so length = 26 inches

$Hope this helps ♥$

Elanso [62]3 years ago

6 0

Answer:

26 inches

Step-by-step explanation:

Let l is length of rectangele and w is width of rectangle.

The formula for perimeter of rectangle is

P = 2l+2w

From question statement, we observe that

l = 3+w eq(1)

and P = 98 in

Putting given values in formula, we have

98 = 2(3+w)+2w

98 = 6+2w+2w

98 = 6 +4w

simplifying , we have

98-6 = 4w

92 = 4w

w = 92/4

w = 23 in

Putting the value of width in eq(1), we have

l = 3+23 = 26 in

Hence, the length of rectangle is 26 inches.

You might be interested in

The area of a circle is 16pi cm2. What is the circle's circumstance?

gavmur [86]

I think you mean circumference...Area is $A= \pi r^{2}$ . We have the area so we need to use it to solve for the radius which we will then use in the circumference formula. $16 \pi = \pi r^{2}$ . Divide both sides by pi to get $\frac{16 \pi }{ \pi } = r^{2}$ . Of course the simplification of the left side gives us $16= r^{2}$ and r = 4. Now fill that in to the circumference formula, which is $C=2 \pi r$ , to get C $C=2 \pi (4)$ which is a circumference of $8 \pi$