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3 years ago

Please help to solve the equations!

1 answer:

8 0

Glad to help, but in my view "helping" means providing you with assistance only after you've begun your own efforts to solve these problems.

Look at <span>3(k+5)=-2(3k-6). Goal: Solve for k.
Multiplying where indicated:

3k + 15 = -6k + 12

Add 6k to both sides: 9k = 12 - 15

dividing both sides by 9: k = -3/9, or k = -1/3 (answer).

Please start one of the other solutions; ask if you have questions about it.</span>

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Dwayne is finding the base of the triangle shown. It's area is 100 square meters. find his mistake and correct it.

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2 years ago

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Write a recursive formula for the following sequence:10, 5, 0, -5,... *

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Answer:

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Step-by-step explanation:

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3 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

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2 years ago

A boat is anchored 2 km south of a lighthouse. The town of Beachton is Located 17 Km East of the lighthouse. What is the distanc

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Answer: the answer is 27.1 km

Step-by-step explanation:

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2 years ago

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The area of a rectangle is 3535 square meter. the width is 2525 meter.

GaryK [48]

A, using the formula length= Area: width
and we have the length= 3535:2525= 1,4 m or this number as a fraction 14/10=7/5
But the length is smaller than the width?

b, I think you type wrongly the problem

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3 years ago