The average is <span>the sum of the data values, divided by the sum of the number of data values </span> 1) [<span>the average weight of pumpkins grown in Cedartown] =[611+753+575+685.5+718]/5--------> 3342.5/5--------> 668.5
the answer Part 1) is the option </span><span>G.) 668.5
</span>2) [the average weight of pumpkins grown in Baytown] =[584+622+713.5+579+644]/5--------> 3142/5--------> 628.5
the answer Part 2) is the option <span>F.) 628.5
</span>The mean absolute deviation is the sum of the absolute values of the differences between each data value and the mean divided by the number of data values
<span>3.the mean absolute deviation of the pumpkin weights in Cedartown mean=</span>668.5<span> =</span>[(668.5-611)+(753-668.5)+(668.5-575)+(685.5-668.5)+(718-668.5)]/5 =302/5--------> 60.4
the answer Part 3) is the option <span>D.) 60.4
</span><span>4.the mean absolute deviation of the pumpkin weights in Baytown </span> mean=628.5 =[(628.5-584)+(628.5-622)+(713.5-628.5)+(628.5-579)+(644-628.5)]/5 =201/5---------> 40.2
the answer part 4) is the option <span>C.) 40.2 </span>
