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shtirl [24]
3 years ago
8

Please help, I need to make and equation and solve it!

Mathematics
1 answer:
Stells [14]3 years ago
6 0
0.15c>10+0.10c
0.05c>10
c>200
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Put these numbers in order from least to greatest. 0.57 5.07 50.7 57 75 ​
nordsb [41]

Answer:

It's basically already in order: 0.57, 5.07, 50.7, 57, 75

Step-by-step explanation:

Hope it helps!      :3

Plz mark as brainliest!

5 0
3 years ago
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Find the term indicated in the expansion. (x - 3y)11; 8th term
Alja [10]
The term in the expansion:
T ( k+1) = n C k * A^(n-k) * B^k.
In this case: n = 11,  k + 1 = 8, so k = 7.
A = x, B = - 3 y
T 8 = 11 C 7 * x^(11-7) * ( - 3 y )^7 =
 =( 11 *10 * 9 * 8 * 7 * 6 * 5 ) / ( 7 * 6 * 5 * 4 * 3 * 2 * 1  )* x^4 * ( - 2,187 y^7 ) =
= 330 * ( - 2,187 ) x^4 y^7 = - 721,710 x^4 y^7
Answer: The 8th term in expansion is
 
8 0
3 years ago
Read 2 more answers
Evaluate –10 • x • 5 when x = –1.<br><br><br> –50<br><br><br> –15<br><br><br> 6<br><br><br> 50
Rudiy27
The answer is 50 ! :-)
4 0
2 years ago
the rectangular metallic block is 30cm long ,25cm broad and8cm high.how many pieces of rectangular slices each of 5mm thick can
Dmitrij [34]

Answer:

12

Step-by-step explanation:

cuz if u put all the fives it takes up for it u would get 12 times five

8 0
3 years ago
A group of engineers is building a parabolic satellite dish whose shape will be formed by rotating the curve y=ax 2 about the y-
Setler79 [48]

Answer:

a = \frac{1}{2}. Surface Area = \frac{4}{3}ft^{2}. and area of the Dish = \frac{4}{3}ft^{2}+pi4^{2} = \frac{4}{3}ft^{2}+50.27=51.6ft^{2}

Step-by-step explanation:

(1) Constant. y(x) = ax^{2} that is the curve that we need to rotate around the y axis to get the parabola with diameter of 8 feet and 2 meter depth that statement is translated in mathematics as x = -4 to 4 and y = 0 to 2.

y max = 2, x max = 4 setting up a equation with a unknown gives

2=a4 and  a = \frac{1}{2}.

so we have now.

y(x) = \frac{1}{2}x^{2} (Done with solving for a Constant).

(2) Surface Area.

Setting Up surface integral.

(i) range in x = 0 to 4.

(ii) range in y = 0 to 2.

integral is.

Integral(0-2)[{integral[(0-4)\frac{1}{32}x^{2}]}]dy

Evaluating this integral gives. \frac{4}{3}ft^{2}.

and area is surface area + area of the circle with 8ft diameter.

= \frac{4}{3}ft^{2}+pi4^{2} = \frac{4}{3}ft^{2}+50.27=51.6ft^{2}...

Note the Difference between area and aurface area.!

6 0
3 years ago
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