Please help, I need to make and equation and solve it!

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

Lerok [7]

Answer:

Q1 - D. f(x) = $x^4-9x^2-50x-150$

Q13 - A. ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Q14 - A. $7x+6+4x^{2}$

Step-by-step explanation:

Question 1:

We know that rational roots always occurs in pairs. So, the zeros of the function will be 5, -3, -1+3i, -1-3i

So, the factored form is $(x-5)(x+3)(x+1-3i)(x+1+3i)=0$

i.e. $(x^2-2x-15)(x+1-3i)(x+1+3i)=0$

i.e. $(x^3-x^2-3ix^2-17x+6ix-15+45i)(x+1+3i)=0$

i.e. $x^4-9x^2-50x-150=0$

Hence, the polynomial function is $f(x)=x^4-9x^2-50x-150$ .

Question 13:

Rational Zeros Theorem states that 'If p(x) is a polynomial with integer coefficients and if $\frac{p}{q}$ is a zero of p(x) = 0. Then, p is a factor of the constant term of p(x) and q is a factor of the leading coefficient of p(x)'.

Let, $\frac{p}{q}$ is a zero of $x^3-7x^2+9x-24=0$ . Then, p is a factor of -24 and q is a factor of 1.

Thus, possible values of p = ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24 and q = ±1

This gives, possible values of $\frac{p}{q}$ are ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Question 14:

We have, f(x) = 7x + 6 and g(x) = $4x^{2}$

Then, (f+g)(x) = f(x) + g(x) = 7x + 6 + $4x^{2}$

So, (f+g)(x) = $7x+6+4x^{2}$

6 0

4 years ago

Charlie's puppy Max, weighs 6 pounds.<br> How many ounces does Max weight?

garri49 [273]

Answer:

96 ounces

Step-by-step explanation:

3 0

3 years ago

Which number property does the following statement represent? 25 × (18 + 82) = (25 × 18) + (25 × 82)

motikmotik

Answer:

Distributive property

342 is correct

Step-by-step explanation:

hope this helps u

8 0

2 years ago

The delivery person weighs 150lb and each box of books weigh 40lb the maximum capacity of the elevator is 1020lb how many box of

padilas [110]

Answer:

21 box of books can be brought up by the delivery person at one time

Step-by-step explanation:

Here, we want to know the number of box of books that the delivery person could bring up at one time.

Let the number of boxes be x , so the total mass of the boxes that could come up at a time will be x * 40 = 40x lb

Let’s add this to the mass of the delivery person = 150 lb

So the total mass going inside the lift would be 150 + 40x

So we have to equate this to the maximum capacity of the lift;

150 + 40x = 1020

40x = 1020 - 150

40x = 870

x = 870/40

x = 21.75

Now since we cannot have fractional boxes, the number of boxes that could come into the lift without exceeding the maximum capacity of the lift is 21

5 0

3 years ago

What is 4+m/8=3/4. Please help me I need your help.

oksian1 [2.3K]

You multiply 8 by both sides and it gives you 4+m=6 and you subtract 4 by both sides and m=2

4 0

3 years ago

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