119.32 = 2 x 3.14 x r
r = 19cm
area = 3.14 x 19^2
= 1133.54cm2
Answer:
tom
Step-by-step explanation:
if you look at samma's rate you can easily find that she was much slower
Volume of a cone, V = πr^2h/3
r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum
Surface area, A = πr [r+ Sqrt (h^2+r^2)] = 3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2
Therefore, minimum amount of paper required is 92.95 cm^2
Answer:
70%
Step-by-step explanation:
The number of students with an April birthday and candles is in the upper left, 14. That’s the “part” Percentage is part/whole x 100.
To figure out the “whole”, you need to add up all the students in the first row of the table, because those are the April birthdays. 14 + 6 = 20
14/20 = 0.7 x 100 = 70%
A:
Area: 289 m
Perimeter: 51 m
B:
Area: 4 m
Perimeter: 8 m
