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3 years ago

5 SIMPLE QUESTIONS 100 POINTS! BEST DEAL OF YOUR LIFE!

Mathematics

2 answers:

Cloud [144]3 years ago

6 0

Hi there!

1. is B) equilateral quadrilateral

2. is 130°

Your friend, ∀SI∀X

jolli1 [7]3 years ago

3 0

Regular quadrilateral

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Cylinder E has the following dimensions: h = 30 cm and r = 4 cm. Cylinder F has the same radius, but has a height of 5 cm . What

Anarel [89]

Answer:

1759.52cm^3

Step-by-step explanation:

Given data

Cylinder E

h = 30 cm and

r = 4 cm

The expression for the volume is

V= πr^2h

V= 3.142*4^2*30

V= 3.142*16*30

V=1508.16 cm^3

Cylinder F

h=5 cm

r = 4 cm

The expression for the volume is

V= πr^2h

V= 3.142*4^2*5

V= 3.142*16*5

V=251.36 cm^3

Hence the total volume is

=251.36+1508.16

= 1759.52cm^3

6 0

3 years ago

I guess no one is helping anymore?

ryzh [129]

Answer:

I guess so.........................................................

8 0

3 years ago

Read 2 more answers

Point A(–4, 2) is reflected over the line x = 3 to create the point A'. What are the coordinates of A'?. . A. (–4, –1). B. (–4,

viva [34]

The answer is D (10,2)

5 0

3 years ago

Learning task 1: Conduct a survey of the favorite fruit of your classmates and/or friends 10 boys and 10 girls by sending a mess

Vlad [161]

Create random data for boys and girls ensuring that the data on each column in equal to 10 . Using that data you can answer the questions .

1. Type of favourite fruits
The rest you need the data for .

8 0

2 years ago

Find the slope of the line through each pair of points (6, -10) , (-15 , 15)

dem82 [27]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\bf \leadsto The \ slope \ of \ the \ line \ is \ \dfrac{-25}{21}.}}}$

<h3>Step-by-step explanation:</h3>

Two points are given to us and we need to find the slope of the line . The slope of the line passing through points $\bf (x_1,y_1 ) \ \& \ (x_2,y_2)$ is given by ,

$\qquad\boxed{\red{\bf Slope = tan\theta=\dfrac{y_2-y_1}{x_2-x_1}}}$

Here , the points are ,

( 6 , -10 )
( -15 , 15 )

$\bf\implies Slope = \dfrac{y_2-y_1}{x_2-x_1} \\\\\bf\implies Slope =\dfrac{15-(-10)}{-15-6} \\\\\bf\implies Slope = \dfrac{15+10}{-21}\\\\\bf\implies Slope =\dfrac{-1(25)}{-1(-21)}\\\\ \bf\implies\boxed{\red{\bf Slope =\dfrac{-25}{21}}}$

<h3>★ Hence the slope of the line joining the two points is -25/21 .</h3>

5 0

3 years ago