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kolezko [41]
4 years ago
10

Solve:​ z5 + 3 = −35

Mathematics
1 answer:
Fudgin [204]4 years ago
8 0

Answer:

z= - 5 √ 38

Step-by-step explanation:

take the root of both sides

or

you can factor each set and make them equal to zero

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What is the value of the given expression when a=3 and b=5?<br> 12a+12b
solniwko [45]
123+125=248




…please if I’m right do mark Brainly-est
5 0
2 years ago
Read 2 more answers
Simplify the ratio-<br><br> 2kg : 3kg : 1.5 kg
katrin [286]

Answer:

1.33kg : 2kg : 1kg

Step-by-step explanation:

2kg : 3kg : 1.5 kg

Given data

We have the ratio

2kg : 3kg : 1.5 kg

Let us reduce the ratio further

2/1.5: 3/1.5 : 1.5/1.5

1.33kg : 2kg : 1kg

Hence the simplified ratio is 1.33kg : 2kg : 1kg

6 0
3 years ago
Please help me with this -2 - (-0.7)
Amanda [17]

Anytime you subtract a negative number, it changes it to adding a positive number.

-2 + 0.7

Since we are adding, we will have an arrow going to the right

-2 + 0.7 = -1.3

Therefore, we will have a point starting at -2, an arrow pointing to the right and stopping at -1.3

Best of Luck!

8 0
4 years ago
Use the upper and lower sums to approximate the area of the region using the given number of subintervals (of equal width)
Mashutka [201]
From the figure shown, the interval is divided into 5 equal parts making each subinterval to be 0.2.

Part A:

y= \sqrt{1-x^2}

The approximate the area of the region shown in the figure using the lower sums is given by:

 Area= [y(0.2)\times0.2]+[y(0.4)\times0.2]+[y(0.6)\times0.2]+[y(0.8)\times0.2] \\ +[y(1)\times0.2] \\  \\ =[\sqrt{1-(0.2)^2}\times0.2]+[\sqrt{1-(0.4)^2}\times0.2]+[\sqrt{1-(0.6)^2}\times0.2] \\ +[\sqrt{1-(0.8)^2}\times0.2]+[\sqrt{1-(1)^2}\times0.2] \\  \\ =(0.9798\times0.2)+(0.9165\times0.2)+(0.8\times0.2)+(0.6\times0.2)+(0\times0.2) \\  \\ =0.196+0.183+0.16+0.12=0.659



Part B:

The approximate the area of the region shown in the figure using the lower sums is given by:

 Area= [y(0)\times0.2]+[y(0.2)\times0.2]+[y(0.4)\times0.2]+[y(0.6)\times0.2] \\ +[y(0.8)\times0.2] \\ \\ =[\sqrt{1-(0)^2}\times0.2]+[\sqrt{1-(0.2)^2}\times0.2]+[\sqrt{1-(0.4)^2}\times0.2] \\ +[\sqrt{1-(0.6)^2}\times0.2] +[\sqrt{1-(0.8)^2}\times0.2] \\ \\ =(1\times0.2)+(0.9798\times0.2)+(0.9165\times0.2)+(0.8\times0.2)+(0.6\times0.2) \\ \\ =0.2+0.196+0.183+0.16+0.12=0.859



Part C:

The approximate area of the given region is given by

Area= \frac{0.659+0.859}{2} = \frac{1.518}{2} =0.759
7 0
3 years ago
What are the first, fourth and eighth terms for A(n)=-2*2^n-1
Advocard [28]
The first term is -2. The fourth term is -16. And the last term is -256.
To find them, lets say the first term, replace n with 1. You can use this idea to find out the rest (which I've already done, but just to explain to you.).
3 0
3 years ago
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