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cestrela7 [59]
2 years ago
10

Javier worked for 5 hours on his science project. The number of hours Emilia worked on her project is represented by the equatio

n shown.
5 × 2 = 10
Which statement accurately compares the number of hours the two students worked?

Javier worked for twice as long as Emilia.
Javier worked for 5 times as long as Emilia.
Emilia worked for twice as long as Javier.
Emilia worked for 5 times as long as Javier.
Mathematics
1 answer:
ale4655 [162]2 years ago
5 0
Emilia worked for twice as long as Javier 
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A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c
olchik [2.2K]
The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in E^{c}. Find P(E^{c}).

Solution:

Part 1:

E^{c} means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

E^{c}=S-E \\  \\ 
E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\  \\ 
E^{c}=(4,5,6)

Thus the set compliment of E will contain the elements {4,5,6}.So

E^{c} = {4,5,6}

Part 2)

P(E^{c}) means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

P(E^{c}) = (Number of Elements in E^{c})/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set E^{c} = n(E^{c})=3

So, 

P(E^{c})= \frac{n(E^{c}) }{n(S)} \\  \\ 
P(E^{c})= \frac{3}{12} \\  \\ 
P(E^{c})= \frac{1}{4}
7 0
3 years ago
Find the least number between 200 and 500 which leaves a remainder of 3 in each case when divided by 8 ,10,12 and 30.
Nookie1986 [14]
Well, that means that it is 3 more than a common multipule of 8,10,12, and 30
find the lcm

8=2*2*2
10=2*5
12=2*2*3
30=2*3*5
lcm=2*2*2*3*5=120
times it by 2 to get it between 200 and 500
240
add 3
243 is da number
5 0
3 years ago
Read 2 more answers
In the algebraic expression 7/y why is coefficient of y? Explain.
dybincka [34]

Answer:

7 is the (constant) coefficient of 1/y, but no, it is not the coefficient of y

Step-by-step explanation:

7/y can be rewritten as 7(1/y) or as 7(y^[-1]).  In this case, yes, 7 is the (constant) coefficient of 1/y, but no, it is not the coefficient of y.

3 0
3 years ago
A number n plus 8 is greater than 11.
Bumek [7]
N+8>11 is the answer you are looking for 

8 0
3 years ago
Completion time (from start to finish) of a building remodeling project is normally distributed with a mean of 200 work-days and
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We should request a completion time of

223 work-days.
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