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Mama L [17]
3 years ago
7

Convert 1 over 8 to a fraction

Mathematics
2 answers:
MArishka [77]3 years ago
6 0
1
-
8 that is the same as 1 over 8
Elis [28]3 years ago
4 0
1 over 8= 1:8= 1/8, so your fraction is 1/8. Hope I helped!
You might be interested in
Simplify expression: <br><br> 3(4x-5) + 4(2x+6)
SVEN [57.7K]
3(4x-5)+4(2x+6)

Distribute.

12x-15+8x+24

12x+8x= 20x

24-15= 9

20x+9 <---- simplified expression

I hope this helps!
~kaikers
6 0
4 years ago
Read 2 more answers
Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0
2 years ago
The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent.Find the single reduction the
Evgen [1.6K]

Answer:

40%  . The single reduction together is 40%.

Step-by-step explanation:

Let the bicycle cost is   x before reduced price.

First 25% is reduced  and again 20% further reduced.

Let the single reduction is y% if the two reduction together are equal.

Solution,

Case .1

reduction cost=x\times 25%%

=x\times 25/100

=x/4

The cost of bicycle after reduction of 25% is

=x-x/4=3x/4

cost of reduction further reduction of 20%      =3x/4\times 20%

=3x\times 20/(4\times 100)

=3x/20

The new cost of bicycle is further reduction of 20% is

=3x/4-3x/20

=\left ( 15x-3x \right )/20

=12x/20=3x/5

Case.2

if single reduction is done new cost of cycle is equal

x-x\times y%=3x/5

x\left ( 1-y/100 \right )=3x/5

\left ( 100-y \right )/100=3/5

100-y=60

y=40%

single reduction of a cycle is 40%

8 0
3 years ago
How to solve all of this
photoshop1234 [79]
Start circle: πd = (3.14)(19) = 59.7

Move diagonally to the circle with the radius of 6.2.

Second circle: 2πr = 2(3.14)(6.2) = 39

Move upwards to the circle with the radius of 10.5

third circle: 2πr = 2(3.14)(10.5) = 66

Move right to the circle with the diameter of 16.6

Fourth circle: πd = (3.14)(16.6) = 52.2

Move down to the circle with the diameter of 7.7

fifth circle: πd = (3.14)(7.7) = 24.2

Move down to the circle with the diameter of 50

Sixth circle: πd = (3.14)(50) = 157.1

Move left to the circle with the radius of 11.8

Seventh circle: 2πr = 2(3.14)(11.8) = 74.1

Move down to the circle with the radius of 38

Eight circle: 2πr = 2(3.14)(38) = 238.8

Move right to the circle with the diameter of 1.1

ninth circle: πd = (3.14)(1.1) = 3.5

Move right to the circle with the radius of 14.8

10th circle = 2πr = 2(3.14)(14.8) = 93

Move up to the end.

Hope this helps :) 
7 0
3 years ago
Is there any tutors orrr
Papessa [141]
There’s tutors for math i just asked a tutor for help lol
4 0
3 years ago
Read 2 more answers
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