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3 years ago

Salim says he cannot simplify the expression a^m • a^n. Complete the statement about Salim's claim.

Mathematics

2 answers:

wlad13 [49]3 years ago

8 0

Answer:

salim CAN simplify this expression because the two factors HAVE the same BASE

a^m x a^n is the same as A^(M+N)

Step-by-step explanation:

Shkiper50 [21]3 years ago

3 0

Answer:

Salim can simplify that and the answer will be $a^m^+^n$

Step-by-step explanation:

This is because of the law of multiplying powers, which states that you can add the exponents if the base is the same. So, you just add m and n and put that as the exponent and you will have the answer.

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Write 28 x 32 in commutative property. No links!

dangina [55]

32 x 28

you just have to flip them, and it'll be commutative! :D

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2 years ago

Is y=3x linear or nonlinear

BlackZzzverrR [31]

Linear that is it ugh i needed to make it 20 characters ok

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3 years ago

National data in the 1960's showed that about 44% of the adult population had never smoked cigarettes. In 1995 a national health

Marta_Voda [28]

Answer:

a) $0.52 - 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.487$

$0.52 + 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.553$

The 95% confidence interval would be given by (0.487;0.553)

b) After see the confidence interval we see that the lower limits 0.487>0.44 with 0.44 or 44% the estimated proportion for 1960, we can conclude that we have a significant increase in the adult proportion had never smoked cigarettes.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

If we replace the values obtained we got:

$0.52 - 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.487$

$0.52 + 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.553$

The 95% confidence interval would be given by (0.487;0.553)

Part b

After see the confidence interval we see that the lower limits 0.487>0.44 with 0.44 or 44% the estimated proportion for 1960, we can conclude that we have a significant increase in the adult proportion had never smoked cigarettes at 5% of significance.

4 0

4 years ago

A manufacturer knows that their items have a normally distributed length, with a mean of 13.2 inches, and standard deviation of

Lana71 [14]

Answer:

0.5358

Step-by-step explanation:

Given

mean = μ = 13.2 inches

and

SD = σ = 2.2 inches

We have to find z-score for the given value 13.4 first

z-score = (x-μ)/σ

= (13.4-13.2)/2.2

=0.2/2.2

=0.0909

We have to find the area to the left of given z-score

The area to the left is 0.5358

So, the probability of choosing an item with length less than 13.4 is 0.5358 ..

5 0

3 years ago

Simplify.<br><br> −9x − 3 − (5x + 3) − 7

Ket [755]

Answer: I got -14x-13

But it sounds wrong but I have a picture

Step-by-step explanation:

4 0

4 years ago