Answer:
$2.25
Step-by-step explanation:
Let "b" be the price of 1 brownie and "c" the price of 1 cookie.
At a bake sale, a student spent $11.00 buying 3 brownies and 5 cookies. Symbolicaly,
3 b + 5 c = 11.00 [1]
His friend spent $3.95 buying 1 brownie and 2 cookies. Symbolicaly,
1 b + 2 c = 3.95
b = 3.95 - 2c [2]
If we replace [2] in [1], we get
3 (3.95 - 2c) + 5 c = 11.00
11.85 - 6c + 5c = 11.00
c = 0.85
If we replace c = 0.85 in [2], we get
b = 3.95 - 2 (0.85) = 2.25
Answer:
a. y^ -1 = e^x +2
Step-by-step explanation:
y = ln (x-2)
Exchange x and y
x = ln (y-2)
Solve for y
Raise each side with a base of e
e^ x = e^(ln(y-2)
e^x = y-2
Add 2 to each side
e^x +2 =y
C=8πab
Divide both sides by 8πb
c/(8πb) = a
Answer:
63m^11 no^12
Step-by-step explanation:
Dont know if thats o or and zero but I solve it by using o..if it was a zero then comment that so I can redo it anyways heres the explanation
(7nm^5 o^2) × (-3m^3 o^5)^2
7m^5 no^2) ×(-3m^3 o^5) ^2
(7m^5 no^2) × (3m^3 o^5)^2
7m^5 no^2 × (3m^3 o^5) ^2
7m^5 no^2 × 9m^6 o^10
63m^11 no^12