The answer is 12:15
The only thing you have to do to get this answer is remove the zero of the number.
When you have a right triangle (A triangle which has a angle of 90°), you can find the "Sine". This is one of the basi trigonometric ratios. By definition, the Sine is:
Sin(α)=Opposite leg/Hypotenuse
You want to find Sin(A), so the opposite leg will be 8√3 and the hypotenuse will be 16.
When you substitue these values, you have:
Sin(α)=Opposite leg/Hypotenuse
Sin(A)=8√3/16
When you simplify, you obtain:
Sin(A)=4√3/8
Sin(A)=2√3/4
Sin(A)=√3/2
Which is the ratio for Sin(A)?
The answer is: The ratio for Sin(A) is √3/2
Answer:
12
Step-by-step explanation:
since 1 inch equals 2.54 cm then 11 inches equals 27.94 cm
27.94 ÷ 2.33 = 11.99
I will use the letter x instead of theta.
Then the problem is, given sec(x) + tan(x) = P, show that
sin(x) = [P^2 - 1] / [P^2 + 1]
I am going to take a non regular path.
First, develop a little the left side of the first equation:
sec(x) + tan(x) = 1 / cos(x) + sin(x) / cos(x) = [1 + sin(x)] / cos(x)
and that is equal to P.
Second, develop the rigth side of the second equation:
[p^2 - 1] / [p^2 + 1] =
= [ { [1 + sin(x)] / cos(x) }^2 - 1] / [ { [1 + sin(x)] / cos(x)}^2 +1 ] =
= { [1 + sin(x)]^2 - [cos(x)]^2 } / { [1 + sin(x)]^2 + [cos(x)]^2 } =
= {1 + 2sin(x) + [sin(x)^2] - [cos(x)^2] } / {1 + 2sin(x) + [sin(x)^2] + [cos(x)^2] }
= {2sin(x) + [sin(x)]^2 + [sin(x)]^2 } / { 1 + 2 sin(x) + 1} =
= {2sin(x) + 2 [sin(x)]^2 } / {2 + 2sin(x)} = {2sin(x) ( 1 + sin(x)} / {2(1+sin(x)} =
= sin(x)
Then, working with the first equation, we have proved that [p^2 - 1] / [p^2 + 1] = sin(x), the second equation.