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nexus9112 [7]
3 years ago
11

Which is another way to write 12x10 exponent 3

Mathematics
2 answers:
bearhunter [10]3 years ago
6 0
12(10^3) is what I would get
adoni [48]3 years ago
3 0
12(10^3) is my answer
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Solve 2x + 4 &gt; 16<br><br> A. x &gt; 10<br> B. x &lt; 6<br> C. x &lt; 10<br> D. x &gt; 6
Salsk061 [2.6K]

Hey there! :)

2x + 4 > 16

We're simply just trying to get x onto it's own side, so let's get rid of any numbers on the same side of it.

We can start out by subtracting both sides by 4.

2x + 4 - 4 > 16 - 4

Simplify.

2x > 12

Then, divide both sides by 2.

2x ÷ 2 > 12 ÷ 2

Simplify.

x > 6

Therefore, our answer is D. x > 6

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6 0
3 years ago
Your firm has a contract to make staff uniforms for a fast-food retailer. The heights of the staff are normally distributed with
FromTheMoon [43]

Answer:

a) 16%

b) 2.5%

Step-by-step explanation:

a)

The mean is 70 with standard deviation(SD) of 3 and you are asked to find out the percentage of staff that have <67(70-3 inch= mean - 1 SD) inch size, which means 1 SD below the mean (<-1 SD). Using 68-95-99.7 rule, you can know that 68% of the population is inside 1 SD range from the mean ( -1 SD to + 1 SD).

To put it on another perspective, there are 32% of the population that have < -1 SD and > +1 SD value. Assuming the distribution is symmetrical, then the value of < - 1 SD alone is 32%/2= 16%

b)

The question asks how many populations have size >76 inches, or mean + 2 SD (70+3*2 inch).

You can also solve this using 68-95-99.7 rule, but you take 95% value as the question asking for 2 SD instead.  Since 95% of population is inside 2 SD range from the mean ( -2 SD to + 2 SD), so there are 5% of population that have < -2 SD and > +2 SD value. Assuming the distribution is symmetrical, then the value of > +2 SD alone is 5%/2= 2.5%

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3 years ago
Estimate 154 divide 7<br>​
Anuta_ua [19.1K]
154 divided by 7 is 22
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Alika [10]

Step-by-step explanation:

Your previous questions answer is

v=23

w=19

x=22

y=26

z=20

<em>if</em><em> </em><em>you</em><em> </em><em>satisfied</em><em> </em><em>in my answers please please mark</em><em> </em><em>as brainleiest and follow me</em><em> </em>

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