What does 3e-6 mean on the calculator?

A bag contains purple marbles and white marbles, 96 in total. The number of purple marbles is 6 less than 5 times the number of

love history [14]

PURPLE MARBLES=P
WHITE MARBLES=W

First, write out an equation showing the number of purple marbles.
P=5W-6
Then, write out the main equation.
W+P=96
W+5W-6=96
Add 6 to both sides.
W+5W=102
6W=102
Divide both sides by 6
W=17
Now that we know there are 17 white marbles, we can go back to the equation about how many purple marbles there are.
P=5W-6
Plug in the value for W, which is 17.
P=5(17)-6
P=85-6
P=79

To make sure your answer is correct, check your work by plugging in the values for P+W=96.
79+17=96
Answer: There are 79 purple marbles.

8 0

3 years ago

A presidential candidate's aide estimates that, among all college students, the proportion who intend to vote in the upcoming el

inessss [21]

Answer:

$z=\frac{0.529 -0.6}{\sqrt{\frac{0.6(1-0.6)}{240}}}=-2.24$

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion college students expressed an intent to vote is not higher than 0.6

Step-by-step explanation:

Assuming the following question: A presidential candidate's aide estimates that, among all college students, the proportion p who intend to vote in the upcoming election is at least 60% . If 127 out of a random sample of 240 college students expressed an intent to vote, can we reject the aide's estimate at the 0.1 level of significance?

Data given and notation

n=240 represent the random sample taken

X=127 represent the college students expressed an intent to vote

$\hat p=\frac{127}{240}=0.529$ estimated proportion of college students expressed an intent to vote

$p_o=0.6$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that at least 60% of students are intented to vote .:

Null hypothesis: $p \geq 0.6$

Alternative hypothesis: $p < 0.6$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.529 -0.6}{\sqrt{\frac{0.6(1-0.6)}{240}}}=-2.24$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion college students expressed an intent to vote is not higher than 0.6

7 0

3 years ago

Integration of (cosec^2 x-2005)÷cos^2005 x dx is

kondor19780726 [428]

We are asked in the problem to evaluate the integral of (cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=∫sec(n−2)xdx+∫tanxsec(n−3)x(secxtanx)dx
Then,
∫tanxsec(n−3)x(secxtanx)dx=tanxsec(n−2)x/(n−2)−1/(n−2)I
we can then integrate the function by substituting n by 3.

On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms

7 0

3 years ago

Which of these equations is in slope intercept form?

AVprozaik [17]

Answer:

$y = \frac{1}{2} x + 6$

Step-by-step explanation:

Remmeber that the slope-intercept form is:

$y = mx + b$

8 0

3 years ago

What is the value of X

Ghella [55]

Answer:

9

Step-by-step explanation:

We have,

Angle GHI = (20x – 8)°
Angle QHI = (14x + 14)°
Angle GHQ = 32°

According to the question,

→ Angle GHQ + Angle QHI = Angle GHI

→ 32° + (14x + 14)° = (20x – 8)°

→ 32° + 14x° + 14° = 20x° – 8°

→ 46° + 14x° = 20x° – 8°

→ 46° + 8° = 20x° – 14x°

→ 54° = 6x°

→ 54° ÷ 6° = x

→ 9 = x

The value of x is 9.

3 0

3 years ago