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stepladder [879]
4 years ago
12

20 points 3 questions

Geography
1 answer:
LenKa [72]4 years ago
4 0
1) <span>No, because shearing causes strike-slip faults or normal faults are caused by tension.

2) </span><span>Diagram A shows a section of rock that contains three different layers. All layers are parallel and are equal in thickness. There are no forces being exerted on the rock layers.

3) </span>Compression: stresses are directed inward - produces thrust faults, reverse faults, or folding; Tension: stresses directed outward
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Task
Yakvenalex [24]

The slope of segment CD is 7. The length of segment BC is √50 units and the figure is a square.

Explanation:

Part A

Slope of a segment is calculated as the ratio of rise over run

In this case, C (8,3) and D(7,-4)

The slope is m=Δy/Δx

Δy=-4-3=-7

Δx=7-8=-1

m= -7/-1 =7

The slope is positive as seen in the graph for segment CD

Part B

To find length of a segment, the formula to apply is:

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2

Given that B(3,8) and C(8,3) then

x₁=3,x₂=8,y₁=8,y₂=3

substitute values in equation as;

d=\sqrt{(3-8)^2 +(8-3)^2} \\\\d=\sqrt{(-5)^2+(5)^2} \\\\d=\sqrt{25+25} \\d=\sqrt{50} \\\\\\d=7.07

The formula used to find length of a segment

Part C

The geometric figure is a Square.The proof is that the length of the segments is equal, √50 units

Lean More

Properties of a square: brainly.com/question/1968511

Keywords : geometric, figure, coordinate, vertices,slope, segment

#LearnwithBrainly

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