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Viefleur [7K]
3 years ago
13

What is the polynomial function of least degree whose only zeros are −4 , 2, and 3?

Mathematics
1 answer:
Alex787 [66]3 years ago
3 0

Answer:

P(x)=x^3-x^2-14x+24

Step-by-step explanation:

The given zeros are −4 , 2, and 3.

Factor Theorem:

  • If a, b and c are the zeros of a polynomial then (x-a) , (x-b) and (x-c) must be the factors. And the polynomial is P(x)=(x-a)(x-b)(x-c)

Using the factor theorem, (x+4), (x-2) and (x-3) are the factors of the polynomial.

Therefore, the polynomial is given by

P(x)=(x+4)(x-2)(x-3)

On simplifying, we get

P(x)=x^3-x^2-14x+24

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The solution to the system of equations is x = 8, y = 4.

<h3>How to write the system of equations?</h3>

First, let's define our variables as x and y.

"the sum of two numbers is twelve" is written as:

x + y = 12

"two times the first number minus three times the second number is four" is written as:

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Then the system of equations is:

x + y  = 12

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<h3>How to solve it?</h3>

First, we isolate one of the variables in one equation, I will isolate x on the first one to get:

x = 12 - y

Now we replace this on the other equation, so we get:

2*(12 - y) - 3y = 4

Now we can solve this for y.

24 - 2y - 3y = 4

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Now we know the value of y, and:

x = 12 - y = 12 - 4 = 8

Then the solution of the system is:

x = 8, y = 4.

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

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