Answer:
In a bumper-to-bumper traffic, when the engine starts overheating the situation can be handled by tapping the accelator which will revive the engine.
Explanation:
Overheating of engine can be due to many reasons. But one should know what to do when an engine overheats in a traffic. Bumper-to-bumper traffic is when the cars are so close in traffic that they touch each other. This usually happens when there's a traffic for a long time or on very busy lane. During summer times, it is important to keep checking the engine temperature to avoid any problem.
When one is stuck in bumper-to-bumper traffic with overheating engine, then there are some meausres that one can take. They are:
- To put the car on park or neutral mode of driving and tap the accelator which will revive the engine.
- The heat can be disperse by rolling down the window and turn the heater up. It will disperse the heat.
Answer:
What if we made a fast game?
Explanation:
The mascot is the person, animal or thing which brings good luck, just like Mario. However, this is not a problem with Sonic the Hedgehog. And the Hedgehog is powerful enough to cross any barrier. Hence tieing the collectibles is not required. And the Hedgehog is quite cute and domestic. But it moves only 10 meters per second if we are considering the maximum speed. Hence, the correct option is certainly what if we made a fast game? And this is option C.
Answer:
In general, scientific evidence are the results of scientific tests used to prove or disprove a theory or hypothesis. In criminal cases, scientific evidence is used to help jurors understand and determine the facts of a case. Explanation:
The answer would be <span>It is designed to promote social interaction and community building.</span>
Answer:
See explaination for the program code
Explanation:
The code below
Pseudo-code:
//each item ai is used at most once
isSubsetSum(A[],n,t)//takes array of items of size n, and sum t
{
boolean subset[n+1][t+1];//creating a boolean mtraix
for i=1 to n+1
subset[i][1] = true; //initially setting all first column values as true
for i = 2 to t+1
subset[1][i] = false; //initialy setting all first row values as false
for i=2 to n
{
for j=2 to t
{
if(j<A[i-1])
subset[i][j] = subset[i-1][j];
if (j >= A[i-1])
subset[i][j] = subset[i-1][j] ||
subset[i - 1][j-set[i-1]];
}
}
//returns true if there is a subset with given sum t
//other wise returns false
return subset[n][t];
}
Recurrence relation:
T(n) =T(n-1)+ t//here t is runtime of inner loop, and innner loop will run n times
T(1)=1
solving recurrence:
T(n)=T(n-1)+t
T(n)=T(n-2)+t+t
T(n)=T(n-2)+2t
T(n)=T(n-3)+3t
,,
,
T(n)=T(n-n-1)+(n-1)t
T(n)=T(1)+(n-1)t
T(n)=1+(n-1)t = O(nt)
//so complexity is :O(nt)//where n is number of element, t is given sum
