Evaluating a piecewise defined function
1 answer:
Given : if x belongs to the interval -2 ≤ x < -1, then f(x) = -2
As x = -2 belongs to the interval -2 ≤ x < -1 ⇒ f(-2) = -2
As x = -1.5 belongs to the interval -2 ≤ x < -1 ⇒ f(-1.5) = -2
Given : if x belongs to the interval 1 ≤ x < 2, then f(x) = 1
As x = 1 belongs to the interval 1 ≤ x < 2 ⇒ f(1) = 1
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6 is in the ten millions place. The number next to 6 is 1, which is less than 5, so you round down. The nearest 10 million is 60,000,000.
180 degrees means that the new x=-x and the new y=-y so
x=3 and y=-5 is orignal
new is -3 and 5
so new oint is
A(-3,5)
X(a+b)-y(a+b)
*factor out (a+b)*
=(a+b)(x-y)
43 maybe? And if I’m wrong in advance-Sorry
No it doesn't. 2*0.5 + 5*0 = 1, not 19
