1.
a. With the picture missing, and 8 appearing in the choices, a can only assume that the spinner has 8 equal sectors.
b. P(Event)=n(Event)/n(Sample space)
c. P(number greater than 2)=n{3,4,5,6,7,8}/n{1,2,3,4,5,6,7,8}=6/8=3/4
2.
a. Sample Space: {2I, 3A, 2M, 2T, H, E, C, N}, n(S)=13
Event T:"selecting T" has a probability of P(T)=n(T)/n(S)=2/13
Event A: "selecting A" has a probability of P(A)=n(3)/n(S)=3/13
Events A and T are mutually exclusive, so P(A or T)=P(A)+P(t)=5/13
3.
a. Event W: white socks, n(W)=3
b. n(Sample space)=n(S)=n(3W, 4B, 2C)=9
c. P(W)=n(W)/n(S)=3/9=1/3
Answer:
$40
Step-by-step explanation:
this is not a mistake, it just turns out that 40% of 40 is 16
9514 1404 393
Answer:
500 cm³
Step-by-step explanation:
The diameter of the sphere is shown as 10 cm, so its radius is 5 cm. Using the given numbers in the given formula, you find the volume to be ...
V = (4/3)(3)(5 cm)³ = 4(125 cm³) = 500 cm³
Answer: We can expect about 40.13% of bottles to have a volume less than 32 oz.
Step-by-step explanation:
Given : The volumes of soda in quart soda bottles can be described by a Normal model with
![\mu=\text{32.3 oz}\\\\\sigma=\text{1.2 oz}](https://tex.z-dn.net/?f=%5Cmu%3D%5Ctext%7B32.3%20oz%7D%5C%5C%5C%5C%5Csigma%3D%5Ctext%7B1.2%20oz%7D)
Let X be the random variable that represents the volume of a randomly selected bottle.
z-score :![\dfrac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
For x = 32 oz
![z=\dfrac{32-32.3}{1.2}=-0.25](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B32-32.3%7D%7B1.2%7D%3D-0.25)
The probability of bottles have a volume less than 32 oz is given by :-
[Using standard normal table]
In percent, ![0.4012937\times100=40.12937\%\approx40.13\%](https://tex.z-dn.net/?f=0.4012937%5Ctimes100%3D40.12937%5C%25%5Capprox40.13%5C%25)
Hence, we can expect about 40.13% of bottles to have a volume less than 32 oz.
Answer:68
Step-by-step explanation:
angle sum property
56+y+y-12=180
44+2y=180
2y=180-44=136
y=136/2
=68
VERIFICATION :56+68+56
=180