Answer:
Step-by-step explanation:
Rewrite this as -m divided by 4 - 2 = 3
Add the two to 3 to get 5
Multiply 5 by 4 to get 20
m = -20
I think it is 64 just multiply 4 times 4 times 4 because of the sides and to find volume you need to multiply the sides and the height so it should be 64.
1. Cross multiply
35x = 5(11)
35x = 55
Divide both sides by 35
x = 55/35
x = 11/7
2. (x - 2)/x = 3/8
Cross multiply
3x = 8(x - 2)
3x = 8x - 16
Subtract 8x from both sides
-5x = -16
divide both sides by -5
x = -16/-5
x = 16/5 OR 3 1/5
3. (a + 1)/(a - 1) = 5/6
cross multiply
6(a + 1) = 5(a - 1)
distribute
6a + 6 = 5a - 5
subtract 5a from both sides
a + 6 = -5
subtract 6 from both sides
a = -11
4. (1/3)x - 4 = (2/3)x + 6
multiply each term by 3 to clear the fractions
x - 12 = 2x + 18
subtract x from both sides
-12 = x + 18
subtract 18 from both sides
-30 = x
Answer:
153 times
Step-by-step explanation:
We have to flip the coin in order to obtain a 95.8% confidence interval of width of at most .14
Width = 0.14
ME = 
ME = 
ME = 

use p = 0.5
z at 95.8% is 1.727(using calculator)





So, Option B is true
Hence we have to flip 153 times the coin in order to obtain a 95.8% confidence interval of width of at most .14 for the probability of flipping a head