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nignag [31]
3 years ago
7

Solve for x. 5x=15+5

Mathematics
2 answers:
Travka [436]3 years ago
6 0

Answer: x=4

Step-by-step explanation:

5x=15+5

15+5=20

5x=20

divide 5 on both sides

20/5=4

x=4

zheka24 [161]3 years ago
3 0

Answer:

x=4

Step-by-step explanation:

5x=15+5    add

5x=20       divide

 x=4           simplify

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iren2701 [21]

Hope this isn't too confusing

3 0
2 years ago
What is an equation of the line that passes through the point (-4,-6)(−4,−6) and is perpendicular to the line 2x-y=62x−y=6?
Alinara [238K]
Are there any answer choices?
5 0
3 years ago
The balance of an investment account is $308 more than the balance 4 years ago. The current balance of the account is $4708. Wha
kifflom [539]

Answer:

$4,400

Step-by-step explanation:

Key: B stands for balance.

b+308=4708

b=4,708-308

b=$4,400

8 0
4 years ago
Is 1500 ml greater than less than or equal to 1.5 l?
Aleks [24]

Is 1500 ml greater than less than or equal to 1.5 l is equal.

4 0
3 years ago
This is for algebra 2 can someone tell me if I’m right and can someone explain how do you get a= ?
algol13

Answers:

a = 2

h = 3

k = -3

You have the correct h and k values. Nice work so far.

==========================================================

Explanation:

(h,k) is the vertex. So (h,k) = (3,-3) meaning h = 3 and k = -3

To get the value of 'a', we need to plug in some point on the red graph. Each point is of the form (x,y). We can pick any point we want that isn't the vertex.

Let's pick (0,3) which is the y intercept. I'm picking this because 0 is an easy number to work with

------------

y = a|x-h| + k

y = a|x-3| + (-3) .... plug in the h,k values

y = a|x-3| - 3

3 = a|0-3| - 3 .... plug in (x,y) = (0,3)

3 = a|-3| - 3

3 = a*3 - 3

3 = 3a - 3

3a-3 = 3

3a = 3+3 ... adding 3 to both sides

3a = 6

a = 6/3 ... divide both sides by 3

a = 2

The value a = 2 indicates that the parent function y = |x| has been stretched vertically by a factor of 2. So it is twice as tall as before. Then it has been shifted to place the vertex at (3,-3) as shown in the graph.

------------

You may be wondering why you can't pick on the vertex for (x,y)

Let's see what happens if we use (x,y) = (3,-3)

y = a|x-3| - 3

-3 = a|3-3| - 3 ... plug in (x,y) = (3,-3)

-3 = a|0| - 3 ... uh oh, we get 0 here

-3 = a*0 - 3

-3 = 0 - 3

-3 = -3

We get a true statement, which is nice, but it doesn't tell us anything about what the value of 'a' is. That 'a' term goes away entirely. So I avoided using x = 3 to prevent x-3 from being 0.

4 0
3 years ago
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