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Mars2501 [29]
3 years ago
15

it giving time saturn was 9.1 times 10 to the eighth power miles from the Sun and Earth was 9.3 times 10 to the seven power mile

s from the Sun. by what distance is one planet close to the Sun than the other planet?
Mathematics
1 answer:
xxMikexx [17]3 years ago
7 0
9.1 * 10^8 is the expression for Saturn. 9.3 * 10^7 is the expression for Earth. Can you figure it out from here?
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9
Rashid [163]

Step-by-step explanation:

1) Your problem → (4x^2 - 17x^3 + 9) - (x^2 + 9x + 23x^2 + 11)

(-17x^3+4x^2+9)-(x^2+23x^2+9x+11)

=-17x^3+4x^2+9-x^2-23x^2-9x-11

=-17x^3+4x^2-x^2-23x^2-9x+9-11

=-17x^3-20x^2-9x-2

2) Your problem → 0 - 19.73 - 25x^2 - 12x - 3

=0-19.73-25x2-12x-3

=-25x^2-12x-22.73

3) - 10.x^3 – 162x^2 – 24x - 4

4) Your problem → 17x^3 - 20x^2 - 9x^2

=17x^3-20x^2-9x^2

=17x^3-29x^2

5) -16x^3 – 243x^2 – 12x – 3

5 0
3 years ago
Find The Distance Between4.5 And -1.4. ( i Need A Answer Right Now Pleaseeeeee!!!!!!
Gwar [14]

Answer:

5.9

Step-by-step explanation:

The distance between a point A and a point B is A-B.  (4.5) - (-1.4) is the same as 4.5 + 1.4 so your answer is 5.9

4 0
2 years ago
Read 2 more answers
a cylinder has a volume of 83 in3 and is 10 in. tall what is the radius of the cylinder in inches use 3.14 and round to the near
lara [203]
Check the picture below.

5 0
3 years ago
Given the following functions f(x) and g(x), solve f over g (−5) and select the correct answer below:f(x) = 2x − 20g(x) = x − 1a
timama [110]

Answer:

(f/g)(-5) = 5

Step-by-step explanation:

You mean, "determine the value of (f/g)(x) at x = -5."

That would be:

f(x)        2x - 20

------- = ------------   and we now substitute -5 for x:

g(x)         x - 1

                  2(-5) - 20      -30

 (f/g)(-5) = --------------- = -------- = 5

                     -5 -1              -6

5 0
3 years ago
Triangle ABC is defined by the points A(2,9), B(8,4), and C(-3,-2).
kotykmax [81]

Answer:

5y - 6x = 8 or y = 6x/5 + 8/5

Step-by-step explanation:

let M1= gradient of line AB and M2= gradient of the second line

When two lines are perpendicular, the product of their gradients is -1

i.e, M1M2= -1

M2= -1/M1

A(2,9) and B(8,4)

gradient= (y2-y1)/(x2-x1)

M1= (4-9)/(8-2)

= -5/6

M2= -1÷ -5/6

-1 × -6/5= 6/5

Equation of the line passing through C(-3,-2)

[y-(-2)]/[x-(-3)= 6/5

(y+2)/(x+3)= 6/5

5(y+2)= 6(x+3)

5y+10=6x+18

5y= 6x + 8

y= 6x/5 + 8/5

7 0
3 years ago
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