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xxTIMURxx [149]
3 years ago
13

Find the product of 1359 and 8

Mathematics
1 answer:
dusya [7]3 years ago
3 0
I believe the answer would be 10,872.
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, list the first five terms of each sequence.<br> f(n + 1) = −2f(n) + 8 and f(1) = 1 for n ≥ 1
svet-max [94.6K]

Answer: 1, 7, 1, 7, 1.

Step-by-step explanation:

The given function :  f(n+1)=-2f(n)+8 and  f(1) = 1 for n ≥ 1

We put value of n=1,2,3,4 , we get

For n=1  , f(2)=f(1+1)=-2f(1)+8=-1(1)+8=-1+8=7

For n=2  , f(3)=f(2+1)=-2f(2)+8=-1(7)+8=1

For n=3  , f(4)=f(3+1)=-2f(3)+8=-1(1)+8=7

For n=4  , f(5)=f(4+1)=-2f(4)+8=-1(7)+8=1

Hence, the  first five terms of the given sequence are 1, 7, 1, 7, 1.

7 0
3 years ago
SOLVE THE EQUATION<br> −9(x + 6) + 60 = 13 − 10x
yuradex [85]

Answer:

x=7

Step-by-step explanation:

−9(x + 6) + 60 = 13 − 10x

Distribute

−9x -54 + 60 = 13 − 10x

Combine like terms

-9x +6 = 13 -10x

Add 10x to each side

-9x+10x +6 = 13-10x+10x

x +6 = 13

Subtract 6 from each side

x+6-6=13-6

x = 7

7 0
3 years ago
How much does mike charge a new customer to ship a package that weighs 50 pounds ? He chargers $40 per pound.
Vera_Pavlovna [14]

Answer:

$2000

Step-by-step explanation:

For each pound, the charge is $40. There are 50 such charges. The point of multiplication is to simplify the process of repeated addition.

... 50 × $40 = $2000

3 0
3 years ago
You must reverse the inequality sign when solving this inequality: x + 7 &lt; 4
SSSSS [86.1K]

I'm not 100% sure what you want me to do with this but i hope this helps:


x < -3

or if you want me to flip the sign then the solution becomes

x > -3

7 0
3 years ago
find the volume of cubical box . if the cost of painting of outer surface is rs 1440 at the rate rs 15 per mcube
bearhunter [10]
Surface of a cubical box=6(side²)

1)We have to calculate the surface of this cubical box.
Rate=cost of painting / surface  ⇒surface=cost of painting/rate

Data:
Rate=$15/m²
cost of painting=$1440

Surface=$1440/($15/m²)=96 m²

2)We find out the length of the side:

Surface of a cubical box=6(side²)

Data:
Surface of a cubical box=96 m2

Therefore:
96m²=6 (side²)
side²=96 m²/6
side²=16 m²
side=√(16 m²)=4 m

3) We find the volume of a cubical box.
volume=(side³)
volume=(4 m)³
volume=64 m³

Answer: the volume of this cubical box would be 64 m³.

3 0
3 years ago
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