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Anna11 [10]
4 years ago
12

Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!

Mathematics
1 answer:
AleksAgata [21]4 years ago
5 0

Answer by JKismyhusbandbae:

\mathrm{Add\:}5\mathrm{\:to\:both\:sides}\\\frac{1}{4}b+\frac{2}{5}b-5+5=-3+5\\Simplify\\\frac{1}{4}b+\frac{2}{5}b=2\\\mathrm{Find\:Least\:Common\:Multiplier\:of\:}4,\:5:\quad 20\\\mathrm{Multiply\:by\:LCM=}20\\\frac{1}{4}b\cdot \:20+\frac{2}{5}b\cdot \:20=2\cdot \:20\\Refine\\5b+8b=40\\13b=40\\\mathrm{Divide\:both\:sides\:by\:}13\\\frac{13b}{13}=\frac{40}{13}\\Simplify\\b=\frac{40}{13}

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Answer:

2

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
The relationship between antioxidant food consumption per day in cups and the BMI of an individual is modeled by the following l
Katena32 [7]
This is in gradient intercept form (or slope intercept form)
y = mx + b
in this case y = -1.2x + 26
so m (the slope) = -1.2
and the y intercept = 26
I'm not sure what intercept they're asking for.
if you wanted to find the x intercept, just substitute.
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8 0
3 years ago
Ca I get help please! I will mark Brainliest if you answer all of these
zalisa [80]

Answer:

E=x=$ 29

Step-by-step explanation:

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x=$58/2

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7 0
3 years ago
What is the area of the rhombus in simplest radical form? The figure is not drawn to scale.
Tanya [424]

The area of the Rhombus is 162√3 sq.unit , Option A is the correct answer.

<h3>What is a Rhombus ?</h3>

A rhombus is a polygon , which has four equal sides , its diagonal bisect each other at 90 degree.

Let x be the half of the other diagonal.

tan 60 = x / 9

x = 9 tan 60

x = 9√3

Area of the Rhombus = (d1 * d2 /2 )

d1 and d2 are the length of the diagonal.

Area of the Rhombus = (9*2)(2 *9√3)/2

Area of the Rhombus =162√3 sq.unit

To know more about Rhombus

brainly.com/question/27870968

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6 0
2 years ago
For X a binomial random variable with n=5 and p=1/4, answer the following
mash [69]
Recall that for X\sim\mathrm{Bin}(n,p), i.e. a random variable X following a binomial distribution over n trials and with probability parameter p,

\mathbb P(X=x)=f_X(x)=\begin{cases}\dbinom nx p^x(1-p)^{n-x}&\text{for }x\in\{0,1,\ldots,n\}\\\\0&\text{otherwise}\end{cases}

So you have

\mathbb P(X=2)=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac34\right)^{5-2}=\dfrac{135}{512}\approx0.26

\mathbb P(2\le X\le4)=\displaystyle\sum_{x=2}^4\mathbb P(X=x)
=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac14\right)^{5-2}+\dbinom52\left(\dfrac14\right)^3\left(1-\dfrac14\right)^{5-3}+\dbinom52\left(\dfrac14\right)^4\left(1-\dfrac14\right)^{5-4}
=\dfrac{375}{1024}\approx0.37

The expected value of X\sim\mathrm{Bin}(n,p) is simply np, while the standard deviation is \sqrt{np(1-p)}. In this case, they are \dfrac54=1.25 and \sqrt{\dfrac{15}{16}}\approx0.97, respectively.
7 0
3 years ago
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