First we have to answers stand that speed is equivalent to the distance traveled in a certain time span. That is speed = distance/time. Conversely, time = distance/speed. We are asked to find the speed going home given, distance, total time and speed going to school. We can answer this equation by adding the time Aidan is spending going and coming back from school
t = (distance to school)/(speed to school) + (distance to home)/(speed to home)
1hour = (16)/(40) + (16)/(speed to home)
Speed to home = 26.67miles/hour
11) x-intercept: 12
y-intercept: 8
12) x-intercept: -18
y-intercept:-16
13) x-intercept: 6
y-intercept:10
Sorry I can't graph it for you but here are the equations in the slope-intercept form
11)y=-2/3x+8
12)y=-8/9x-16
13)y=-5/3x+10
Answer:
B
Step-by-step explanation:
Answer:
Let the angle be x.
Its complement is 90°-x° and its supplement is 180°- x.
If 90°-x = (1/2)(180°-x) then 180°- 2x = 180° -x => 180°-180° = 2x-x => x= 0°
Hence the statement is true only for 0°
