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labwork [276]
3 years ago
13

Which statement is NOT always true?

Mathematics
1 answer:
BartSMP [9]3 years ago
3 0
B. The product of two irrational numbers if rational

Example: The square root of 2 times the square root of 3, is the square root of 6, which is still irrational. 
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Given the two expressions shown below:
kobusy [5.1K]
<h2>Answer: A. Both are rational.</h2>

Step-by-step explanation:

Although both expressions have square roots, the result of each square root is an integer, which can be expressed as a fraction.

In this sense:

Rational numbers are all numbers that can be represented as the quotient (division) of two integer numbers. This means they can be represented as a fraction in which the denominator is nonzero.

If we solve both expressions, we will be able to see that the result is an integer that can be expressed as a fraction with two integers:

\sqrt{4} + \sqrt{25}=2 + 5= 7 The result is an integer

7=\frac{7}{1}

\sqrt{4} + \sqrt{9}= 2 + 3=5 The result is an integer

5=\frac{5}{1}

7 0
3 years ago
(52) Pleaase check ym answer
Alinara [238K]
X = measure of each of the legs
"perimeter is 8 more than 2 times one of the legs" ---> P = 2x+8
P = 28 is the given perimeter

So,
P = 2x+8
28 = 2x+8
2x+8 = 28
2x = 20
x = 10

If x = 10, then the two legs add up to x+x = 10+10 = 20
Leaving P-20 = 28-20 = 8 inches left over for the base

You have the correct answer (choice D, 8 inches) though your steps are a bit confusing at some parts. Such as the part where you wrote 2x = 10 twice. I think I know what you were trying to say. 

4 0
3 years ago
Pls help on part A B and C plssssss
Fittoniya [83]
Part be just and all the cost and c i cant do good luck hope that helps
6 0
3 years ago
Read 2 more answers
Help me hurry please
saul85 [17]

Answer:

28x + 8y + 2

Step-by-step explanation:

Combine like-terms within the parentheses, then distribute -2.

Hope this helps! :)

3 0
3 years ago
Read 2 more answers
Evaluate exactly without the use of a calculator (remember to rationalize any denominators). a.(cos 60o)(sin 270o) + tan 225o b.
Rom4ik [11]

Given:

The trigonometric expressions are given as,

\begin{gathered} a)\text{ }(\cos 60\degree)(\sin 270\degree)+\tan 225\degree \\ b)-\tan 240\degree+(cos45\degree)(\sec 135\degree) \end{gathered}

Explanation:

a)

The given expression can be rewritten as,

=(\cos 60\degree)(\sin (360\degree-90\degree))+\tan (270\degree-45\degree)\text{ . . . .  .(1)}

Since, from the trigonometric ratios,

\begin{gathered} \sin (360\degree-90\degree)=-\sin 90\degree \\ \tan (270\degree-45\degree)=\cot 45\degree \end{gathered}

On plugging the obtained ratios in equation (1),

=(\cos 60\degree)(-\sin 90\degree)+\cot 45

Substitute the trigonometric values in the above equation.

\begin{gathered} =\frac{1}{2}(-1)+1 \\ =-\frac{1}{2}+1 \\ =\frac{1}{2} \end{gathered}

Hence, the exact value of the expression is 1/2.

b)

The given expression can be rewritten as,

=-\tan (270\degree-30\degree)+(\cos 45\degree)(\sec (90\degree+45\degree))\text{ . . . ..(2)}

Since, from the trigonometric ratios,

\begin{gathered} \tan (270\degree-30\degree)=\cot 30\degree \\ \sec (90\degree+45\degree)=-\csc 45\degree \end{gathered}

On plugging the obtained ratios in equation (2),

=-\cot 30\degree+(\cos 45\degree)(-\csc 45)

Substitute the trigonometric values in the above equation.

\begin{gathered} =-\sqrt[]{3}+\frac{1}{\sqrt[]{2}}(-\sqrt[]{2}) \\ =-\sqrt[]{3}-1 \end{gathered}

Hence, the exact value of the expression is -√3-1.

7 0
1 year ago
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