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3 years ago

Find the surface area of the cone in terms of pie if the radius is 7 n the side is 10

Mathematics

1 answer:

Margarita [4]3 years ago

8 0

The surface area of a cone is the sum of the area of its circular base and the lateral area.

... S = πr² +πrh = πr(r+h) . . . . . for radius r and slant height h

Filling in the given numbers, you get

... S = π·7·(7+10) = 119π

The surface area is 119π square units.

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The length of a rectangle is 3 yards more than twice the width x the area is 629 yd.²

madam [21]

Answer:

The length is 37yd

The width is 17yd

Step-by-step explanation: please see attachment for explanation

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3 years ago

What is the distance between (6, 2) and (-3, -2)?

Yakvenalex [24]

Answer:

√97 ≈ 9.85 units

Step-by-step explanation:

The distance formula can answer this question.

d = √((x2 -x1)^2 +(y2 -y1)^2) = √((-3-6)^2 +(-2-2)^2) = √(81 +16) = √97

The distance between the points is √97 ≈ 9.85 units.

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4 years ago

Which of the following is true about the base b of a logarithmic function?

Svetach [21]

The base b of a logarithmic function should be greater than zero and not equal to 1. Therefore, the first and second choice is the only ones left possible:

b> 0 and b = 1
b > 0 and b=/ 1

but it was stated earlier that the value of b should not be equal to 1, therefore, the answer is

b > 0 and b =/ 1<span />

5 0

3 years ago

Read 2 more answers

0.06y + 200 = 0.03y + 350

LenaWriter [7]

350.03 thats the answer the y might be a variable

7 0

3 years ago

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The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 – 5t2, where t is the tim

Leno4ka [110]

<h2>Time Interval : 1 sec to 1.414 sec</h2>

Step-by-step explanation:

The height of the stuntperson jumping off a $20\text{ }m$ is modelled as $h\text{ }=\text{ }20\text{ }-\text{ }5t^{2}$ . Here $t$ is the time in seconds.

We have to record the person when he is between the heights $15\text{ }m\text{ and }10\text{ }m$ from the ground.

When $h\text{ }=\text{ }15$ ,

$15\text{ }=20\text{ }-\text{ }5t^{2}\\5t^{2}\text{ }=\text{ }5\\t^{2}\text{ }=\text{ }1\\t\text{ }=\text{ }1\text{ }sec$

When $h\text{ }=\text{ }10$ ,

$10\text{ }=20\text{ }-\text{ }5t^{2}\\5t^{2}\text{ }=\text{ }10\\t^{2}\text{ }=\text{ }2\\t\text{ }=\text{ }\sqrt{2}\text{ }=\text{ }1.414\text{ }sec$

The stuntperson is at height $15\text{ }m$ at $t\text{ }=\text{ }1\text{ }sec$ , and is at height $10\text{ }m$ at $t\text{ }=\text{ }1.414\text{ }sec$ .

∴ The camera should film the person for the time interval $\textbf{1}\text{ }sec\text{ to }\textbf{1.414}\text{ }sec$ .

5 0

3 years ago

Read 2 more answers