Answer:
The weight of box and pocking material
pound
Step-by-step explanation:
Let the weight of box and packing material 
weight of package
pounds
total weight
pound

Subtract both side by 

Hence weight of box and packing material
pound
Yes! The lengths of each side must be less than the sum of the other two lengths. It looks like this:
4+4>7
7+4>4
4+7>4
Step-by-step explanation:
From the given question it appears that (n-1) is in the numerator's place, if it is so, then let us solve it.

Answer:
What is the length of a rectangle if the width is
10 centimeters and the diagonal is 16 centimeters?
Step-by-step explanation:
Answer: what’s the question ?