#1 is true. The term they have in common is y with an invisible coefficient in-front of the second y term
#2 has zero like terms. 15 has no variable, and the other terms have different variables.
#3 has two like terms, that’s 9 and 8 which add to equal 17. The answer is 3x + 17 aka D.
#4 has two like terms, the numbers with the variable ‘n’. 4n + 7n = 11n. Your answer is 11n + 12 aka D
[ 4(4) x 4(3) ] / 4(5)
= [4(4+3)] / 4(5)
= 4(7) / 4(5)
= 4(7-5)
= 4(2)
Answer: 13300
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Work Shown:
A = event that it rains
B = event that it does not rain
P(A) = 0.30
P(B) = 1-P(A) = 1-0.30 = 0.70
Multiply the attendance figures with their corresponding probabilities
- if it rains, then 7000*P(A) = 7000*0.30 = 2100
- if it doesn't rain, then 16000*P(B) = 16000*0.70 = 11200
Add up the results: 2100+11200 = 13300
This is the expected value. This is basically the average based on the probabilities. The average is more tilted toward the higher end of the spectrum (closer to 16000 than it is to 7000) because there is a higher chance that it does not rain.
C - 0.15c is the same as 1c - 0.15c.
1 - 0.15 = 0.85.
Joe can also use 0.85c.
Answer:
82
Step-by-step explanation:
50+32 =82 and this has to be longer so this is me making it longer
