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Vadim26 [7]
4 years ago
6

How do I solve the equation above?

Mathematics
2 answers:
Anon25 [30]4 years ago
6 0
4 1/3 x 6 = 26 + 5 =31
Hatshy [7]4 years ago
3 0
At first glance it seems thought but it’s really not. You need to split the equation into 2 parts. One is the fraction and the other is whole number. In this case multiply 6 by 4 and then multiply 1/3 by 6 and add. Out numbers together. Hope I could help!
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Estimate to the nearest 0.5 unit and classify the extrema for the graph of each function.
VLD [36.1K]

f(x) = x^3+x^2-x

Finding the extreme point :

f'(x)=3x^2+2x-1=0\\\\3x^2+3x-x-1=0\\\\3x(x+1)-1(x+1)=0\\\\(3x-1)(x+1)=0\\\\x=\dfrac{1}{3}\ ,\ x=-1

Now,

f''( x ) at x = 1/3 and -1 is :

f''(x)=6x+2\\\\f''(1/3)=4  \\\\f''(-1)=-4

Therefore, it is maximum at x = -1 and minimum at x = 1/3 .

Hence, this is the required solution.

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3 years ago
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mr Goodwill [35]
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Find the distance between -2 3/5 and -2 3/10
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Answer:

the distance in between is (0,5)

3 0
4 years ago
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vesna_86 [32]

The number closer to zero is C

5 0
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Rama09 [41]

Answer:

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