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Mariana [72]
3 years ago
11

Please help, I will mark!!

Mathematics
1 answer:
Alik [6]3 years ago
6 0

Answer:

d=28.28

Step-by-step explanation:

To calculate the lenght of the diagonal d across the square, we can assume that the square it is compound of two right triangles. So, we can resolve this exercise using The Pythagorean Theorem.

<em>The Pythagorean theorem</em> states that in every right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the respective lengths of the legs. It is the best-known proposition among those that have their own name in mathematics.

If in a right triangle there are legs of length a and b, and the measure of the hypotenuse is c, then the following relation is fulfilled:

a^{2} +b^{2} =c^{2} a is the height, b is the base, and c is  

the hypotenuse.

To obtain the value of the hypotenuse

c= \sqrt{a^{2} +b^{2} }

To find the value of the lenght of the diagonal d across the square, we have:

d=\sqrt{a^{2} +b^{2} } Where a = b = 20

Substituting the values

d=\sqrt{(20)^{2} +(20)^{2} }\\d=\sqrt{400+400} =\sqrt{800} \\d=28.284

Round the answer to 2 decimal places

d=28.28

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Joe bought 16 pounds of flour for $7.<br> How many pounds of flour did he get per dollar?
wolverine [178]

Answer:

112

Step-by-step explanation:

7 0
3 years ago
Evaluate without using a calculator (x2y-3)0+x1/3-(4x)1/2 when x = 64 and y = 27. Show work.
aleksley [76]

Given:

The expression is:

(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}

To find:

The value of the given expression when x=64 and y=27.

Solution:

We have,

(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}

Putting x=64 and y=27, we get

=((64)^2(27)-3)^0+(64)^{\frac{1}{3}}-(4(64))^{\frac{1}{2}}

It can be written as

=((64)^2(27)-3)^0+(4^3)^{\frac{1}{3}}-(4)^{\frac{1}{2}}(64)^{\frac{1}{2}}

=1+4-2(8)           [\because a^0=1,a\neq 0]

=5-16

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Therefore, the value of the given expression -11 when x=64 and y=27.

4 0
3 years ago
Figure A is a scale image of Figure B.
Sauron [17]

<em>Greetings from Brasil...</em>

According to the statement, one figure is scaled in relation to another, so we can apply similarity to polygons.....

So

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27/X = 45/35

OR

35/45 = X/27

27/X = 45/35

45X = 27·35

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X = 945/45

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Evaluate the following 32^4/5
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8 0
3 years ago
Can you comment the answer because for some reason it won't show up :)​
Finger [1]

D. 7 1/5

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3 years ago
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