We have the following:
solving for x
The solution of x is equal to 28, therefore 12 is not a solution of the equation
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
6x+12y-6z+7x7y-28z= 13x+19y-34z
Answer:
140%
Step-by-step explanation:
28-10 = 14 person enrolled
14/10 = 140%
Answer:
1.26 m cubed
Step-by-step explanation:
1.4*.5*1.8= 1.26
