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katrin2010 [14]
3 years ago
8

What is 124 decreased by 67%

Mathematics
2 answers:
lbvjy [14]3 years ago
7 0

Answer:

40.92

Step-by-step explanation:

hope this helps

inysia [295]3 years ago
5 0

Answer:

40.92

Step-by-step explanation:

hope this helps

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Bob will rent a car for the weekend. He can choose one of two plans. The first plan has an Initial fee of $60 and costs an addit
shepuryov [24]

Answer:

Step-by-step explanation:

+55+%2B+.5x+=+.7x+

+.2x+=+55+

+x+=+275+

3 0
2 years ago
ii. A machine is sold for 7,000/-. The gross loss is 20% of the cost. What are the cost and gross loss?
aleksley [76]

Given:

Selling price of a machine = 7000/-

Gross loss = 20%.

To find:

The cost and gross loss.

Solution:

Let x be the cost of machine.

According to the question,

x-20\%\text{ of }x=7000

x-\dfrac{20}{100}x=7000

x-0.2x=7000

0.8x=7000

Divide both sides by 0.8.

x=\dfrac{7000}{0.8}

x=8750

So, the cost of the machine is 8750/-.

Now,

\text{Gross Loss}=\text{Cost}-\text{Selling price}

\text{Gross Loss}=8750-7000

\text{Gross Loss}=1750

Therefore, the gross loss is 1750/-.

8 0
2 years ago
Patti's Pet Palace has an 85-gallon fish tank. When it needs to be cleaned, it can be drained at a rate of 2 gallons per minute.
QveST [7]

Answer:

c y=2x-85 I think so please check if I'm wrong

I think c

6 0
3 years ago
Read 2 more answers
In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.
WARRIOR [948]

Answer:

For First Solution: y_1(t)=e^t

y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:y_2(t)=cosht

y_2(t)=cosht  is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: y_1(t)=e^t

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_1(t)=e^t

First order derivative:

y'_1(t)=e^t

2nd order Derivative:

y''_1(t)=e^t

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

2nd order Derivative:

y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

3 0
3 years ago
HELP ME WITH THIS PLEASE. THANK YOU
lesya [120]

Answer:

I think it's 2

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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