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aleksley [76]
3 years ago
11

Let u = (-1,3) and w (2,4) find the resulting vector of 2u-4w in component form

Mathematics
1 answer:
weqwewe [10]3 years ago
7 0

The answer is A.(-10,-10)

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What is the difference between no solution and no real solution? When do you get multiple solutions? This is for solving absolut
shepuryov [24]
No solution means u can graph the two equations and it would form parallel lines and would never intersect while, no real solution when graph the two equations would form the same line. When dealing with absolute value equation an equation with a degree larger than one,theres a chance it can be multiple solutions
7 0
3 years ago
Suppose that 18 inches of wire costs 72 cents.
NeX [460]

Answer:

41 inches of wire will cost 164 cents.

Step-by-step explanation:

1st Method

Use proportions!

18/ 72 = 41/ c

Cross multiply

18 * c = 72 * 41

18c = 2952 divide both sides by 18

<em>c = 164</em>

2nd Method.

Find the rate of the costs. r = rate

18*r = 72

r = 4 cents/inch

Now that you've found the rate you can multiply it by 41 inches to find the cents the wire costs!

41 inch * r (cents/inch)          inches cancels out.

41 * 4 = 164

<em>164 cents</em>

7 0
3 years ago
Find the value of the unknown number in the proportion 17/80=p/100
rjkz [21]
17/80 = p/100

p = 17/80 * 100

p = 0.2125 * 100

p = 21.25
8 0
4 years ago
Mario is constructing a frame for a 10 in .by 8 in. photo. He wants the frame to be the same width all the way around and the to
alexgriva [62]
(10+2x)(8+2x) = 120
4x^2 + 36x + 80 = 120
x^2 + 9x + 20 = 30

x^2 + 9x - 10 = 0

(x+10)(x-1) = 0

x = 1 inch dimension
8 0
4 years ago
Read 2 more answers
A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte
monitta

Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if it is 0.7 or less, that is:

H_0: \mu \leq 0.7

At the alternate hypothesis, we test if it is greater than 0.7, that is:

H_1: \mu > 0.7

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that \mu = 0.7

Survey of 35 people. From the sample, the mean difference was 0.95, with a standard deviation of 0.44.

This means that n = 35, X = 0.95, s = 0.44

Calculate the test statistic

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{0.95 - 0.7}{\frac{0.44}{\sqrt{35}}}

t = 3.36

The test statistic is t = 3.36.

7 0
3 years ago
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