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11111nata11111 [884]
3 years ago
15

I need help on this question

Advanced Placement (AP)
2 answers:
Phoenix [80]3 years ago
5 0
Chemical properties
UNO [17]3 years ago
4 0

I'm pretty sure it's chemical properties.

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The subjects' daily caffeine intakes were measured by evaluating their food diaries, where they recorded everything they consume
bogdanovich [222]

Hi Thaddeush13,

Biases - " lacking a neutral viewpoint, or not having an open mind".

The potential biases that could hapen in this experiment are different intakes or types of coffee. For Example, Cold, Hot, Caramel. And each as a different size. Sugar intake is also another problem here.

3 0
3 years ago
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Compare and contrast United States society in the 1920’s and the 1950’s with respect to two of the followings:
Sergio039 [100]

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Look at the actions listed below and select ALL that are good safety practices in the workplace. Then, select the Submit button.
Vladimir79 [104]

Answer:

I don't see any actions, but I found these examples online

Not taking unnecessary risks.

Always look out for hazards.

Always use Personal Protective Equipment (PPE)

If you must smoke, do so only in designated areas.

Keep your work area clean and tidy.

Enter and leave the workplace using proper routes.

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4 0
2 years ago
How do you find the degrees of a vector? Specifically this one.
lara [203]
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3 years ago
Limit as x approaches 0 of (2e^x-2)/x
Snowcat [4.5K]

Answer:

Explanation:

\lim_{x \to \ 0} \frac{2e^x-2}{x}

So first, we have to plug in zero and see if we can evaluate this limit simply from that.

When we plug in zero we get: (2e^0-2)/0

e^0 is 1 so we have 2-2/0 or 0/0. So we have an indeterminate form type 0/0.

This means we have to apply L'Hospital's Rule.

As a reminder L'Hospitals Rule is \lim_{x\to \ c} \frac{f'(x)}{g'(x)}

Meaning that we take the derivative of the top and bottom function as the approach some value "c". We can do this with a 0/0 indeterminate form.

So:

The derivative of 2e^x - 2 is just 2e^x

and the derivative of x is 1

So we are left with \lim_{x \to \ 0} 2e^x

Plugging in zero we see this gives us 2 as 2(e^0) = 2(1) = 2.

Hence, \lim_{x \to \ 0} \frac{2e^x-2}{x} = 2

3 0
3 years ago
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