Splitting up [0, 3] into 
equally-spaced subintervals of length 
gives the partition
![\left[0, \dfrac3n\right] \cup \left[\dfrac3n, \dfrac6n\right] \cup \left[\dfrac6n, \dfrac9n\right] \cup \cdots \cup \left[\dfrac{3(n-1)}n, 3\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%20%5Cdfrac3n%5Cright%5D%20%5Ccup%20%5Cleft%5B%5Cdfrac3n%2C%20%5Cdfrac6n%5Cright%5D%20%5Ccup%20%5Cleft%5B%5Cdfrac6n%2C%20%5Cdfrac9n%5Cright%5D%20%5Ccup%20%5Ccdots%20%5Ccup%20%5Cleft%5B%5Cdfrac%7B3%28n-1%29%7Dn%2C%203%5Cright%5D)
where the right endpoint of the 
-th subinterval is given by the sequence
for 
.
Then the definite integral is given by the infinite Riemann sum
If x=4, rewrite the equation which would be 5(4)+6
First you multiply 4 by 5 which would give you 20
Now put in the 6 in the equation
20+6
20+6=26
Therefore for the expression given the value of x would make your answer be 26
Dividing both sides by-3
the division sign will still be the same
your answer is c>2
