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notsponge [240]

3 years ago

14

We have just moved to geometry. Any help? This is just practice as well

1 answer:

Vera_Pavlovna [14]3 years ago

8 0

Answer:

rotation of 270 counterclock wise

Step-by-step explanation:

Since none of the other ones are correct and man i miss geometry i'm in Ap calc and i don't recommend haha.

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PLZ HELP want to know if its right

Paraphin [41]

Answer:

60° is answer.it is right.thank you

8 0

2 years ago

What is the simplified form of the expression 1/3(21m + 27)?

Lana71 [14]

1/3 ( 21m + 27 )
= 1/3 X 21m + 1/3 X 27
= 7m + 9 ..

Hope it helps !!!
if u hav any doubt then u can ask ....

5 0

3 years ago

Read 2 more answers

Solve the following absolute value equations. Show the solution set and check your answers. |0.3-3/5k|-0.4=1.2

9966 [12]

Answer:

**The equation is not clear, so I have provided both options**

<h3><u>Option 1</u></h3>

$\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5}k\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5}k=1.6$

$\implies -\dfrac{3}{5}k=1.3$

$\implies k=-\dfrac{13}{6}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5}k)=1.6$

$\implies -0.3+\dfrac{3}{5}k=1.6$

$\implies \dfrac{3}{5}k=1.9$

$\implies k=\dfrac{19}{6}$

<h3><u>Option 2</u></h3>

$\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5k}\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5k}=1.6$

$\implies -\dfrac{3}{5k}=1.3$

$\implies -3=6.5k$

$\implies k=-\dfrac{6}{13}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5k})=1.6$

$\implies -0.3+\dfrac{3}{5k}=1.6$

$\implies \dfrac{3}{5k}=1.9$

$\implies 3=9.5k$

$\implies k=\dfrac{6}{19}$

6 0

1 year ago

What is the mode of this data set? 35,36,35,38,37,38,38,38,33,40,34,36,36,38,39,38,37,33,37,38,36,32,36,37,32

denpristay [2]

Answer:

38

Step-by-step explanation:

The most occuring number is the mode, which in this case is 38.

7 0

2 years ago

Read 2 more answers

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nevsk [136]

A function is a relation for which each value from the set the first components of the ordered pairs is associated with exactly one value from the set of second components of the ordered pair.

3 0

2 years ago