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4 years ago

URGENT!! How do I solve this?

2 answers:

5 0

A the 15th day because, the least common multiple of 15, 3, and 5
Sorry I wrote this answer but forgot to send I hope you understand :3

Anna11 [10]4 years ago

3 0

A.) the 15th day, because you would the less common multiple is 15 of 3 and 5.

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IPS Math Grade 7 Final SY20-21 1 5 of 13

miv72 [106K]

Answer:

Actual distance between two city = 40 miles

Step-by-step explanation:

Given sample size;

1 inch = 10 miles

Distance between two city = 4 inch

Find:

Actual distance between two city

Computation:

Actual distance between two city = Sample size of 1 inch in miles x Distance between two city

Actual distance between two city = 4 x 10

Actual distance between two city = 40 miles

8 0

3 years ago

Which box plot correctly displays the data set with a maximum of 24, a minimum of 3, a median of 15, an upper quartile of 19, an

sashaice [31]

Answer:

its C

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Show the work pls <br> thanks

Liono4ka [1.6K]

(26 - 6) : 2 =

20 : 2 =

10 feet

4 0

3 years ago

Exercise 2.64. On a test there are 20 true-or-false questions. For each problem the student (a) knows the answer with probabilit

ale4655 [162]

Answer:

$\left(p+\dfrac{p}{2}\right)^{19}\left(20-19p-\dfrac{19r}{2}\right)$

Step-by-step explanation:

Let the probability that he gets the correct answer be m.

If he gets the answer, then either he knows it (a probability of p) or he does not know it but guesses correctly (r × 1/2). Therefore,

$m = p + \dfrac{r}{2}$

Let the probability that he gets the incorrect answer be n. Then, by being complementary events

$n=1-m =1 - p - \dfrac{r}{2}$

This is a binomial or Bernoulli distribution since he gets the answer either correctly or incorrectly. The probability of at least 19 correct answers out of 20 is the sum of the probabilities of 19 or 20 correct answers.

$P(\gt19) = P(19) + P(20)$

$P(\gt19) = \binom{20}{19}m^{19}n^1 + \binom{20}{20}m^{20}$

$P(\gt19) = 20\left(p + \dfrac{r}{2}\right)^{19}\left(1 - p - \dfrac{r}{2}\right) + \left(p + \dfrac{r}{2}\right)^{20}$

$= \left( p + \dfrac{r}{2}\right)^{19}\left(20\left(1 - p - \dfrac{r}{2}\right)+p + \dfrac{r}{2}\right)$

$P(\gt19) = \left(p+\dfrac{p}{2}\right)^{19}\left(20-19p-\dfrac{19r}{2}\right)$

3 0

4 years ago

One pound of gummy bears costs $2.20. How much does 1.6 pounds cost?

vladimir1956 [14]

You have to multiply 2.20 x 1.6 = 3.52

8 0

3 years ago